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Lisa [10]
3 years ago
7

Answer number 1 or 2 or both please<3

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

1. 1.96 g/L

2. 1 g/cm³

Step-by-step explanation:

Density is found by dividing mass by volume: d = m/v.

1.

We know that the mass is 0.196 grams, while the volume is 100 mL.

Converting the volume to liters, we get:

100 mL = 0.1 L

Then, applying our density formula:

d = m/v

d = 0.196 g / 0.1 L = 1.96 g/L

2.

Here, we know that the mass is 27 grams. However, we don't know the volume, which we need to find.

The block of wood is 3 cm on all sides, which means it's a cube. The volume of a cube is denoted by V = s³, where s is the side length. Here, s = 3, so V = s³ = 3³ = 27 cm³.

Applying our density formula gives:

d = m/v

d = 27 g / 27 cm³ = 1 g/cm³

<em>~ an aesthetics lover</em>

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3a+4b= c solve for b
Alina [70]

Answer:

b = (c - 3a)/4

Step-by-step explanation:

3a + 4b = c

4b = c - 3a

b = (c - 3a)/4

6 0
2 years ago
Find the perimeter.
Scorpion4ik [409]

Answer:

7 1/3 inches

Step-by-step explanation:

2 (1 3/4 + 1 11/12)

9+11

3/4+11/12= -------------

12

20/12

=1 2/3+ 2

2(3 2/3)

= 7 1/3

7 0
2 years ago
A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure anti
Murrr4er [49]

With amounts measured in gallons, let

x = amount of 65% antifreeze

y = amount of 90% antifreeze

1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.

To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have

x + y = 120 … … … … … [total volume of antifreeze solution]

0.65x + 0.90y = 96 … [total volume of pure antifreeze]

Solve the first equation for y :

y = 120 - x

Substitute this into the second equation and solve for x :

0.65x + 0.90 (120 - x) = 96

0.65x + 108 - 0.90x = 96

0.25x = 12

x = 48

Solve for y :

y = 120 - 48

y = 72

6 0
1 year ago
Hi can anyone plz help me with this and can you explain how you got it ​
zloy xaker [14]

Answer:

What to prove, solve for?

6 0
3 years ago
Read 2 more answers
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
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