Answer:
t cannot be -5 or 0 because these cause a 0 in the denominator and you cant divide by 0 that I'm aware of
Answer:
2 solutions
Step-by-step explanation:
x^4-6x^2-7=0
Replace x^2 by y
(x^2)^2-6x^2-7=0
y^2-6y-7=0
D=b^2-4ac= (-6)^2-4*1*(-7)= 36+28=64
sqrtD=8
y1=(-b-sqrtD)/2a=-2/2=-1
y2= (-b+sqrtD)/2a=14/2=7
x^2=-1(n0 roots) x^2=7 x=sqrt7 or x=-sqrt7
2 roots
Answer:
A. n5+4 B. (4+n)5 C.(4+n)/5 D.(n*n)3 E. (n*3) 2
Step-by-step explanation:
I am not good at explaining but for E. the 2 will be squared but I am not sure how to type it out so Hope this can help ;)
Find the length of the hypotenuse
34^2 + 27^2 = c^2
1156 + 729 = 1885
c^2 = 1885
sqrt(1885)
c = 43.42
First, lets transform the given vector into an unit vector (dividing by its module)
UnitVec = 4/5 i + 3/5 j
Then lets change this vector into a polar form
UnitVec = 1. with angle of 36.869 degrees taking as a reference the i vector
Then, the probem tells us that the vectors u and v make an angle of 45 degrees with UnitVec, so lets add+-45 to the vector in polar form
U = 1*[cos(36.869 +45)i + sin(36.869 +45)j] = 0.1414 i + 0.9899 j
V = 1*[cos(36.869 -45)i + sin(36.869 -45)j] = 0.9899 i - 0.1414 j
