Answer:
Ten and a Half milkshakes can be prepared from the available amount of ice cream.
Step-by-step explanation:
The total vanilla ice cream = 7/8 gallons
Ice cream used for 1 milkshake = 1/12 gallon
Now, total number of milkshakes possible = ![\frac{\textrm{Total availibility of ice cream}}{\textrm{Ice cream used for each milkshake}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextrm%7BTotal%20availibility%20of%20ice%20cream%7D%7D%7B%5Ctextrm%7BIce%20cream%20used%20for%20each%20milkshake%7D%7D)
= ![\frac{\frac{7}{8} }{\frac{1}{12} } = \frac{7}{8} \times \frac{12}{1} = 10.5](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B7%7D%7B8%7D%20%7D%7B%5Cfrac%7B1%7D%7B12%7D%20%7D%20%20%3D%20%5Cfrac%7B7%7D%7B8%7D%20%20%5Ctimes%20%5Cfrac%7B12%7D%7B1%7D%20%20%3D%2010.5)
Hence ten and a half milkshakes can be prepared from the available amount of ice cream.
Cylinder (A):
-Surface area: adding all areas of all faces of the shape.
*10 x 6= 60m^3
*3.14 x 3^2 = 28.274 m^2. Then We times it by 2 since we have 2 circles. Which equals to 56.55m^2
Total surface area: 60 + 56.55 = 116.55m^2
-Volume: 3.14 x r^2 x h, then substitute.
*3.14 x 3^2 x 10 = 282.74m^3
(B):
-surface area:
*7 x 11= 77
*5 x 11 = 55
*11 x 11 = 121
*7 x 5 = 35/2 = 17.5 > then again we times it by 2 cuz we have 2 triangles. Which equals to 35.
Total surface area: 77 + 55 + 121 + 35 = 288 cm^2
-Volume:
*7 x 5 x 11 = 385 cm^3
Make sure to check the units!!!
Hope this helped :)
Answer:
a) r = 0.974
b) Critical value = 0.602
Step-by-step explanation:
Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below
Test A | 64 48 51 59 60 43 41 42 35 50 45
Test B | 91 68 80 92 91 67 65 67 56 78 71
To find - (a) What is the value of the linear coefficient r ?
(b) Assuming a 0.05 level of significance, what is the critical value ?
Proof -
A)
r = 0.974
B)
Critical Values for the Correlation Coefficient
n alpha = .05 alpha = .01
4 0.95 0.99
5 0.878 0.959
6 0.811 0.917
7 0.754 0.875
8 0.707 0.834
9 0.666 0.798
10 0.632 0.765
11 0.602 0.735
12 0.576 0.708
13 0.553 0.684
14 0.532 0.661
So,
Critical r = 0.602 for n = 11 and alpha = 0.05
Answer- 4x-6
explain- i got it right
Solution: We are given below data:
![2, 8, 10, 16](https://tex.z-dn.net/?f=%202%2C%208%2C%2010%2C%2016%20)
Now to find the mean deviation, we use the below formula:
![MD= \frac{\sum|X-\bar{X}|}{N}](https://tex.z-dn.net/?f=%20MD%3D%20%5Cfrac%7B%5Csum%7CX-%5Cbar%7BX%7D%7C%7D%7BN%7D%20)
Where:
represents the summation
X, represents the observation.
represents the mean
N represents the number of observation.
![\bar{X}= \frac{\sum{X}}{N}= \frac{2+8+10+16}{4}=9](https://tex.z-dn.net/?f=%20%5Cbar%7BX%7D%3D%20%5Cfrac%7B%5Csum%7BX%7D%7D%7BN%7D%3D%20%5Cfrac%7B2%2B8%2B10%2B16%7D%7B4%7D%3D9%20)
![\sum |X-\bar{X}| = |2-9| + |8-9| +|10-9| +|16-9|=7+1+1+7=16](https://tex.z-dn.net/?f=%20%5Csum%20%7CX-%5Cbar%7BX%7D%7C%20%3D%20%7C2-9%7C%20%2B%20%7C8-9%7C%20%2B%7C10-9%7C%20%2B%7C16-9%7C%3D7%2B1%2B1%2B7%3D16%20)
Therefore, the mean deviation is:
![MD= \frac{16}{4}](https://tex.z-dn.net/?f=%20MD%3D%20%5Cfrac%7B16%7D%7B4%7D%20)
= 4