This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Answer:
The value of pi is equal to 3.14
Answer: Q= -31
Step-by-step explanation:
Answer:
(a;b)={(17; 64); (64; 17)}
Step-by-step explanation:
a+b=81 => b=81-a
a*b=1088
a*(81-a)=1088
-a²+81a=1088
a²-81a+1088=0
a²-64a-17a+1088=0
a(a-64)-17(a-64)=0
(a-17)(a-64)=0
=> a=17 and a=64
for a=17 => b=81-17=64
for a=64 => b=81-64=17
(a;b)={(17; 64); (64; 17)}
