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serg [7]
3 years ago
13

X2-2=0 what is the solution to this equation?

Mathematics
1 answer:
puteri [66]3 years ago
4 0

Answer:

I am going to assume that you meant x^2:

x = sqrt 2

Step-by-step explanation:

x^2 - 2 = 0

x^2 = 2

x = sqrt 2

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Work out the surface area of the shapes in the attached file
grin007 [14]

Answer:

Find the area of every shape

12 x 9 = 108. Don't divide because there is two

12 x 14 = 168

14 x 9 = 126

15 x 14 = 210

108 + 168 + 126 + 210 = 612

____________________

2 x pi x radius x height + 2 x radius x radius x height

466.5

Step-by-step explanation:

6 0
3 years ago
HELP asap AB=85m Find the length of Line CD
Aleks [24]
CD = x
BC = y
AB = 85
BD = BC+CD = y+x

tan(angle) = opposite/adjacent
tan(28) = BC/AB
tan(28) = y/85
85*tan(28) = y
y = 85*tan(28)
y = 45.1953016912257

tan(angle) = opposite/adjacent
tan(31) = BD/AB
tan(31) = (y+x)/85
tan(31) = (45.1953016912257+x)/85
85*tan(31) = 45.1953016912257+x
51.0731526173427 = 45.1953016912257+x
51.0731526173427-45.1953016912257 = 45.1953016912257+x-45.1953016912257
5.877850926117 = x
x = 5.877850926117

So CD is roughly 5.877850926117 meters

8 0
3 years ago
Which measure of central tendency is MOST EASILY affected by outliers
Serjik [45]
The average can be easily affected by outliers because an outlier can bring the average much higher or lower depending on the value. For example, if this was the data set

0,50,51,52
 the average would be 38.25

But without the 0, the average would be 51.<span />
5 0
3 years ago
A rectangle is constructed with its base on the​ x-axis and two of its vertices on the parabola y equals = 100 100 minus −x squa
masha68 [24]

Answer:

Step-by-step explanation:

Given that a rectangle is constructed with its base on the x axis and two of its vertices on the parabola

y=100-x^2

This parabola has vertex at (0,100) and symmetrical about y axis.

Any general point above x axis can be written as (a,b) (-a,b) since symmetrical about yaxis.  

Hence coordinates of any rectangle are

(a,0) (-a,0), (a, 100-a^2), (-a, 100-a^2)

Length of rectangle = 2a and width = 100-a^2

Area of rectangle = lw = 2a(100-a^2)=200a-400a^3

To find max area, use derivative test.

A' = 200-800a^2\\A"=-1600a

Hence maxima when first derivative =0

i.e. when a =2

Thus we find dimensions of the rectangle are l =4 and w = 96

Maximum area = 4(96) = 384

5 0
3 years ago
What is 100 more than 291
Dmitry [639]
It is 391 because 1+0=1, 9+0=9, and 1+2=3
5 0
3 years ago
Read 2 more answers
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