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serg [7]
3 years ago
13

X2-2=0 what is the solution to this equation?

Mathematics
1 answer:
puteri [66]3 years ago
4 0

Answer:

I am going to assume that you meant x^2:

x = sqrt 2

Step-by-step explanation:

x^2 - 2 = 0

x^2 = 2

x = sqrt 2

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Need Help!!! ASAP
RoseWind [281]

Answer:

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}

Step-by-step explanation:

The given probabilities are:

P(red)=\frac{2}{7}

P(blue)=\frac{3}{14}

Their sum is P(red)+P(blue)=\frac{2}{7}+\frac{3}{14}

The probabilities that will complete the model should add up to \frac{1}{2} so that the sum of all probabilities is 1.

P(green)+P(yellow)=\frac{2}{7}+\frac{2}{7}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}=\frac{1}{2}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}

P(green)+P(yellow)=\frac{5}{21}+\frac{11}{21}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}=\frac{1}{2}

5 0
3 years ago
What's rate of $ 7.96 for 5 pounds
BartSMP [9]
To find the rate, we have to divide both numbers by 5. So the rate will be $1.592 for 1 pound.
7 0
3 years ago
Fimd the angles marked with letters <br>Please help! ​
damaskus [11]

Answer:

a=64° alternating angles

b=40° corresponding angles

3 0
3 years ago
Read 2 more answers
) a, p and d are n×n matrices. check the true statements below:
BigorU [14]
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose \mathbf P is the matrix of the eigenvectors of \mathbf A, and \mathbf D is the diagonal matrix of the eigenvalues of \mathbf A:


\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}

\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}

Then

\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}

In other words, the columns of \mathbf{AP} are \mathbf{Av}_i, which are identically \lambda_i\mathbf v_i, and these are the columns of \mathbf{PD}.

c. False. A counterexample is the matrix

\begin{bmatrix}1&1\\0&1\end{bmatrix}

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

\begin{bmatrix}0&1\\0&0\end{bmatrix}

with eigenvalue \lambda=0 and eigenvector \begin{bmatrix}k&0\end{bmatrix}^\top, where k\in\mathbb R. But the matrix can't be diagonalized.
7 0
3 years ago
Find the a if c = 5<br> ;;;;;;
Tatiana [17]

Answer:

Step-by-step explanation:

Solve this by writing an equation of ratios:

 1        a

----- = -----

√3     5

                                        5

Then 5 = √3*a, or a = -----------

                                       √3

                                                        5√3

Rationalize the denominator:  a = ----------

                                                             3

8 0
2 years ago
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