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guapka [62]
3 years ago
7

Jessica moved into her sister's old room after she moved to college. The dimensions of her old room were 10 ft long by 9ft feet

wide. The perimeter of her new room was 57 ft. By what scale factor did the dimensions of her old room change?
Mathematics
1 answer:
kozerog [31]3 years ago
5 0
It is 36 to 57 for the ratio.
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NEED HELP ASAP!!!!
Genrish500 [490]

Answer:

B) Jill omitted a factor pair, which affected the GCF and factored expression.

Step-by-step explanation:

Jill is factoring the expression 13xy-52y. Her work is shown below.  

Factors of 13xy: 1, 13, x, y  

Factors of 52y: 1, 2, 26, 52, y       OOPSIE  she forgot 4,13

GCF: y

Factored expression: y(13x-52)   13y (x-4)

4 0
3 years ago
Read 2 more answers
the sides of a triangle, in centimetres,are x,2x-3 and 2x+5. The perimeter of the triangle is 57 cm.a)write down an equation for
soldier1979 [14.2K]

Answer:

11 cm, 19 cm, 27 cm

Step-by-step explanation:

Triangles have 3 sides and perimeter is the sum of all side lengths. So the equation is x + (2x-3) + (2x+5) = 57.

x + (2x-3) + (2x+5) = 57

x + 2x - 3 + 2x + 5 = 57

x + 2x + 2x - 3 + 5 = 57

5x + 2 = 57

5x = 57 -2

5x = 55

x = 11

Now that we know the value of x, we can figure out the side lengths. The first side (x) is 11 cm long, the second side (2x - 3) is 19 cm, and the third side (2x + 5) is 27 cm long.

6 0
2 years ago
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WILL AWARD A MEDAL AND FIVE STARS!!!!
ycow [4]
Hello,

f(x)-2x-7

g(x)=-4x+3

(fog)(x)=f(g(x))=f(-4x+3)=-2(-4x+3)-7=8x-6-7=8x-13

(fog)(-5)=8*(-5)-13=-53

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3 years ago
Which fraction is equivalent to <br> 2<br> 10
yawa3891 [41]

Answer:

Fraction Equivalent Fractions

1/5 2/10 4/20

2/5 4/10 8/20

3/5 6/10 12/20

4/5 8/10 16

Step-by-step explanation:

THIS IS ANSWER PLS MARK BRAINLIST

7 0
2 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
Dvinal [7]
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:


..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation:  , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
4 0
3 years ago
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