gold density = 38.6 *10^-3 / 2 *10^-6 = 19300 Kg/m3
Iron density = 46.8 *10^-3 / 6 *10^-6 = 7800 Kg/m3
water mass = density*volume = 1 * 10 = 10 grams = 0.01 Kg
The increase the magnitude of the electric force ;
1) The charges on the objects must be increased
2) The distance of separation between the objects must be reduced.
<h3>
What is electric field?</h3>
The term electric field has to do with the region where the electric force on an object is expirieced. We must the note thate electric force is a result of the influence of a charge on another.
The increase the magnitude of the electric force ;
1) The charges on the objects must be increased
2) The distance of separation between the objects must be reduced.
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Answer:
Option B is correct
Explanation:
acceleration is equal to rate of change of velocity.
For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C
Answer: 10.3m/s
Explanation:
In theory and for a constant velocity the physics expression states that:
Eq(1): distance = velocity times time <=> d = v*t for v=constant.
If we solve Eq (1) for the velocity (v) we obtain:
Eq(2): velocity = distance divided by time <=> v = d/t
Substituting the known values for t=15s and d=155m we get:
v = 155 / 15 <=> v = 10.3