Solve using quadratic equations

Mathematics

1 answer:

Volgvan4 years ago

8 0

Answer:

x= -1. x= -5/2. use an app eather photomath or brainly

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What is 5r^(2)-14r+ 8 = in general trinomial

eimsori [14]

Answer:

STEP

Equation at the end of step 1

(5r2 - 14r) + 8

Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .

-40 + -1 = -41

-20 + -2 = -22

-10 + -4 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4

5r2 - 10r - 4r - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

5r • (r-2)

Add up the last 2 terms, pulling out common factors :

4 • (r-2)

Step-5 : Add up the four terms of step 4 :

(5r-4) • (r-2)

Which is the desired factorization

Final result :

(r - 2) • (5r -4)

8 0

3 years ago

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Find the break-even point if TC(x) =5x +10000 and R(x) =15x

Finger [1]

15,000 I believe. I don't have a lot of experience with this

3 0

4 years ago

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The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?

denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

$PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5$

All sides have the same lengths.

2. Find the slopes of all lines:

$PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}$