An item is regularly priced at $90 . leila bought it at a discount of 60% off the regular price. how much did leila pay?

Consider the irrational number 73 . Between what two integers is the value of this number? A) 6 and 7 B) 7 and 8 C) 8 and 9 D) 9

andrew11 [14]

A) 6² and 7² , 36 and 49 not this one
B) 7²=49 and 8²=64 not this one
C) 8²=64 and 9²=81 , so 8 and 9, correct answer

7 0

3 years ago

(please zoom / zoom out if needed to see question. (: )

eduard

You can find the area of the rectangle and the triangle separately and then add them together which would result in 330in. I personally do not think you should use the trapezoid formula even though they said it is a trapezoid (a trapezoid is usually not shaped like that) but if you want to it would result in 270in.

3 0

3 years ago

The volume of a cylinder is given by the formula , where r is the radius of the cylinder and h is the height. Which expression r

kotykmax [81]

The Volume of cylinder represented by the option B.

According to the statement

we have given that the volume formula of cylinder is V= (pi)r^2h, and we have to find that the which expression verify the volume formula for the cylinder given in diagram.

So,

We know that height of the cylinder is given by h = 2x + 7 and

radius r = x - 3.

We know that the formula of volume of cylinder is:

Volume of a cylinder = (pi)r^2h

and Substituting the given values in the above formula

And the volume becomes

Volume = (pi)r^2h

Volume = (pi)( x-3 )^2 (2x+7)

Volume = (pi) ( x^2 + 9 - 6x ) (2x+7)

Volume = (pi) ( 2x^3 + 7x^2 +18x +63 - 42x)

So, The Volume of cylinder represented by the option B.

Learn more about Volume here brainly.com/question/1972490

Disclaimer: This question is incomplete. Please find the full content below.

Question:

The volume of a cylinder is given by the formula V= pi^2h, where r is the radius of the cylinder and h is the height: which expression represents the volume of this cylinder?

a) Volume = (pi) ( 3x^3 + 7x^2 +14x +63 - 42x)

b) Volume = (pi) ( 2x^3 + 7x^2 +18x +63 - 42x)

c) Volume = (pi) ( 7x^3 + 7x^2 +11x +63 - 42x)

d) Volume = (pi) ( 11x^3 + 7x^2 +13x +63 - 42x)

#SPJ4

7 0

1 year ago

What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m

Shtirlitz [24]

Answer:

60.6528 kg

Step-by-step explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

$V=\frac{4}{3}\pi r^3\\\\V=\frac{4}{3}\pi (\frac{18}{100})^3\\\\V=\frac{4}{3}\pi (0.005832)\\\\V=0.007776$

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

$\rho=\frac{mass}{volume}\\ \\7800\: kg/m^3=\frac{mass}{0.007776\: m^3}\\\\mass=60.6528\:kg$

Thus, the mass of the solid ball of iron is 60.6528 kg

8 0

3 years ago

What is the simplified expression for:

kari74 [83]

81=3^4
I hope this helps! Good luck!

5 0

3 years ago