Answer:
Captive portal.
Explanation:
A Wi-Fi can be defined as a wireless local area network that allows network devices such as access points (APs), computers (both laptops and desktops), smartphones, smart televisions, etc., to communicate with each other wirelessly over a short-ranged network. It is a standard communication network that uses radio waves to establish a channel (medium) between multiple network devices.
In this scenario, when Flavio first connects to a Wi-Fi, a webpage appears requiring him to first agree to an Acceptable Use Policy (AUP) before continuing. Thus, the type of access point (AP) he encountered is a captive portal.
A captive portal can be defined as a webpage that's been designed on a networking device to be viewed and interacted with by the user of a public-access network such as a Wi-Fi, before he or she is granted an access to the network (internet).
Answer:
OR
Explanation:
"OR" expands a search by telling the database that any of the words it connects are acceptable. This is particularly beneficial when you are searching for synonyms, such as “the victorian age” OR “sexual puritanism”
So, if you type in “the victorian age” OR “sexual puritanism”, your results will include articles with either term, but not necessarily both.
The <em><u>sound energy into electric energy and then into radiant energy.</u></em>
<em>[That's it]:)</em>
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
<span>A network with 6 bits remaining for the host portion will have 62 usable hosts. The netmask is </span><span>255.255.255.192/26, the shorthand is [6-bit] which is equal to the number of addresses as <span>= 62 hosts + 1 bcast + 1 net base</span></span>
