Answer:
x = 3 + √6 ; x = 3 - √6 ;
; 
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:

for the equation ax² + bx + c = 0
thus,
the roots are

or

or
and, x = 
or
and, x = 
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are

or

or
and, x = 
or
and, x = 
or
and, x = 
or
and, 
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ;
; 
Answer:

or

Considering ![\theta \in (0, 2\pi]](https://tex.z-dn.net/?f=%5Ctheta%20%5Cin%20%280%2C%202%5Cpi%5D)

or

Step-by-step explanation:

We have:

Therefore,

or

---------------------------------

or

Hello,
n=1,2,3,.... and not 0
Answer B a(n)=-2*n
Answer:
it is D because it is asking for the opposite of -4 so it would be the tick mark on -4 and 4
Step-by-step explanation: