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hjlf
2 years ago
6

Which quadrilaterals always have two pairs of congruent opposite angles?

Mathematics
1 answer:
drek231 [11]2 years ago
4 0
Parallelograms. Rectangles. Trapezoids.
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Big Time Movers charges an initial fee of $24.50, plus $12.75 an hour for their moving services. On holidays, they charge 2.5 ti
stiv31 [10]
2.5(12.75x + 24.50) = 188.75
31.875x + 61.25 = 188.75
31.875x = 188.75 - 61.25
31.875x = 127.50
x = 127.50 / 31.875
x = 4....they worked 4 hrs
5 0
3 years ago
Read 2 more answers
Please I need your help ASAP
dolphi86 [110]

Answer:

D

Step-by-step explanation:

B has a y-intercept of 4, greater than A's y-intercept of -4. This means that D is correct.

7 0
2 years ago
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Write the slope intercept form of a line that passes<br> through (3, -2) and is 1 to y = x + 3.
zhuklara [117]

Answer:12

Step-by-step explanation:

8 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
Add. Write your answer as a fraction in simplest form.<br> -4/8 + (-23/18)
abruzzese [7]

Answer:

sorry i need more points

Step-by-step explanation:

8 0
3 years ago
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