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vodomira [7]
3 years ago
8

What is x ? And how do I solve for it ?

Mathematics
1 answer:
Kaylis [27]3 years ago
6 0

I believe it might be that x would be negative six. A triangle is supposed to sum to 180 degrees. An equation could be 180 = 52 + 78 + 56 + x.

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Suppose f(x)=x^2. What is the graph of g(x)=1/2f(x)?
sp2606 [1]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph of g(x) is a vertically scaled version of the graph of f(x). The scale factor is 1/2, so vertical height at a given value of x is 1/2 what it is for f(x). This will make the graph appear shorter and fatter than for f(x).

The graph of g(x) is attached.

6 0
3 years ago
A geologist noticed that a land along a fault line moved 24.8 centimeters over the past 175 years . On average, how much did the
olasank [31]

Answer:

On average, the land moved 0,14 cm each year.

Step-by-step explanation:

To know how much did, on average, the land move,  we should divide the total number of cm over the total number of years:

x=24.8 cm/175 years

x=0,1417 cm each year

If we divide years over cm we will get x in years each cm, which is wrong.

Because the problem asks for the answer rounded to the hundredths place:

x= 0,14 cm each year

8 0
3 years ago
4 ounce bottle of medicine contains 20 doses how many doses are in a 13 ounce of all of the same medicine
NNADVOKAT [17]
\bf \begin{array}{ccllll}
ounces&doses\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
4&20\\
13&x
\end{array}\implies \cfrac{4}{13}=\cfrac{20}{x}

solve for "x"
3 0
3 years ago
Read 2 more answers
Quadrilateral ABCD was dilated with the origin as the center of dilation to create quadrilateral EFGH on the graph below.
Marianna [84]

Answer:

(x,y)(0.4x, 0.4y) is the answer for your question

3 0
3 years ago
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
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