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4 years ago

What is the sale price on a painting that has a regular price of $1,700 and is on sale for 25% off the regular price ?

Mathematics

1 answer:

cluponka [151]4 years ago

8 0

Answer:$425

Step-by-step explanation: Of you have a painting that is $1700 and is on sale for a week for example, you would take your percent and move the decimal to the left TWO times and put /100 over it, and then multiply it by 1700/10, and there's your answer. Cross simplify if you can.

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In planning her retirement, Liza deposits some money at 4.5% interest, with twice as much deposited at 5%. Find the amount depos

AlekseyPX

Let

x ----> amount deposited at 4.5%

y ----> amount deposited at 5%

we have that

y=2x----> equation A

4.5%=0.045

5%=0.05

0.045x+0.05y=1,595 ----> equation B

solve the system

substitute equation A in equation B

0.045(x)+0.05(2x)=1,595

solve for x

0.045x+0.10x=1,595

0.145x=1,595

x=11,000

Find y

y=2(11,000)=22,000

<h2>The amount deposited at 4.5% was $11,000 and the amount deposited at 5% was $22,000</h2>

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1 year ago

Jason has $70 in a savings account that earns 5% interest, compounded annually.

kvv77 [185]

Answer:

$77.18

Step-by-step explanation:

A = total amount

P = principal

I = interest

A = P(1 + r/n)^n·t

A = 70(1+.05)²

A = 70(1.05)²

A = 77.175

I = A - P

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3 years ago

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3 years ago

La siguiente figura representa una torre de transmisión de energía eléctrica: ¿Mediante cual razón trigonométrica se puede deter

lana [24]

Answer:

B. sen α = BC/b

Step-by-step explanation:

Las identidades trigonométricas se utilizan para resolver problemas de ángulos rectos.

En un ángulo recto, el lado al que se hace referencia como opuesto es el lado opuesto al ángulo, el lado al que se hace referencia como adyacente es el lado siguiente al ángulo (entre el ángulo y el ángulo recto) mientras que la hipotenusa es el lado más largo (opuesto al ángulo recto)

De identidades trigonométricas:

$sen\ \alpha=\frac{lado\ opuesto}{hipotenusa} \\\\lado\ opuesto=BC=a\\\\hipotenusa=b\\\\sen\ \alpha=\frac{lado\ opuesto}{hipotenusa} =\frac{BC}{b} \\\\sen\ \alpha =\frac{BC}{b}$

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3 years ago

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kozerog [31]

Answer:

Step-by-step explanation:

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3 years ago

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