For this problem you must do Pythagorean theorem:
![a^{2} + b^{2} =c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3Dc%5E%7B2%7D)
In this example 10ft is c and 7ft is a (or it could be b, and you'll be solving for a instead of b. It's the same thing, since a and b are both legs)
Plug what you know into the equation:
![7^{2} +b^{2} = 10^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3D%2010%5E%7B2%7D)
49 +b^{2} = 100
Bring 49 to the right side by subtracting it:
b^{2} = 51
Now you still must isolate b. The opposite of squaring is taking the square root so take the square root of both sides to cancel it from the left side:
![b =\sqrt{51}](https://tex.z-dn.net/?f=b%20%3D%5Csqrt%7B51%7D)
b = 7.1414
b ≈ 7 ft
Hope this helped!
Answer:
![x = 9.7](https://tex.z-dn.net/?f=x%20%3D%209.7)
Step-by-step explanation:
Given
The attached triangle
Required
Find x
Using law of sine, we have:
![\frac{a}{sin A} = \frac{b}{Sin B}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bsin%20A%7D%20%3D%20%5Cfrac%7Bb%7D%7BSin%20B%7D)
So, we have:
![\frac{x}{sin 32} = \frac{18}{Sin 100}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bsin%2032%7D%20%3D%20%5Cfrac%7B18%7D%7BSin%20100%7D)
Make x the subject
![x = \frac{18 * sin 32}{Sin 100}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B18%20%2A%20sin%2032%7D%7BSin%20100%7D)
![x = \frac{18 * 0.5299}{0.9848}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B18%20%2A%200.5299%7D%7B0.9848%7D)
![x = 9.685](https://tex.z-dn.net/?f=x%20%3D%209.685)
-- approximated
Answer:
66
Step-by-step explanation:
B is 57
C is 57
180 - (57 x 2) =
180 - 114 = 66
Answer:
T = 4x - 5
Step-by-step explanation:
Let x = Ben's age
2x = Chloe's age
x - 5 = Dan's age
Combine all the terms and simplify to form an equation.
T = 2x + x + x -5
T = 4x - 5