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vesna_86 [32]
4 years ago
9

Find 41% of 48 Please this is hard

Mathematics
1 answer:
laiz [17]4 years ago
5 0
I hope this helps you



%41.48




41.48/100




1968/100



19,68
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Forgive me if I’m wrong. 25?
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A survey records many variables of interest to the researchers conducting the survey. The following are some of the variables fr
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The correct option is D

Step-by-step explanation:

A categorical variable is a variable that can take on one of a limited, and usually fixed, number of possible values, assigning each individual or other unit of observation to a particular group or nominal category on the basis of some qualitative property. Example of categorical variables are race, sex group and education level.

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Can someone please explain to me how to solve this problem? I have the answer already all I need is to know how to solve the pro
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6 times the difference of a number and 4 equals 7
Nonamiya [84]
6( x - 4) = 7
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Many people use scanners to read documents and store them into pdf file. To help determine which brand of scanner to buy, a stud
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The data is missing in the question. The data is provided below :

Document : 1     2      3      4      5     6      7      8

Brand A       17  29    18    14    21   25    22    29

Brand B       21  38    15    19    22   30    31   37

Solution :

State of the hypothesis of the null hypothesis and alternate hypothesis.

Null hypothesis : $h_A = h_B$

Alternate hypothesis : $h_A > h_B$

These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.

Significance level = 0.05

Therefore the standard error is :  $SE = \sqrt{(\frac{s^2_1}{n_1})+(\frac{s^2_2}{n_2})}$

                                                         = 3.602

And the degree of freedom, DF = 14

$t=\frac{(x_1-x_2)-d}{SE}$

 = -1.319

Here, $s_1$ = standard deviation of the sample 1

        $s_2$ = standard deviation of the sample 2

         $n_1$ = size of the sample 1

        $n_2$ = size of the sample 2

         $x_1$ = mean of the sample 1

        $x_2$ = mean of the sample 2      

          d = the hypothesis difference between the population mean

The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P($t \leq -1.32$) = 0.1042  

Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.

But from the test, we have no sufficient evidence that supports that Brand A is better than Brand B.      

8 0
3 years ago
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