Answer:
Second option is the right choice.
Step-by-step explanation:
Divide the second equation by -5 and you'll get the equation same as first equation.
So, it has infinite many solutions.
Answer:
Okay! What is your question? I have the evaluate part.
Please hold while I validate your prescription.
Step-by-step explanation:
Let d = number of stamps from John (4 letters, d is 4th letter, etc)
<span>Let e = number of stamps from Johan </span>
<span>Let h = number of stamps from Jonathan </span>
<span>Johan and Jonathan have the same number of stamps, so: </span>
<span>e = h </span>
<span>2 times Johan's collection is 11 less than 5 times John's collection, so: </span>
<span>2e = 5d - 11 </span>
<span>3 times Jonathan's collection is 3 less than 7 times John's collection,so: </span>
<span>3h = 7d - 3 </span>
<span>Now we have three equations and three unknowns. You're asked for the number of stamps in John's collection, so you want the value to variable "d". </span>
<span>Since e = h, we can substitute "h" for "e" in the second equation. </span>
<span>2h = 5d - 11 </span>
<span>3h = 7d - 3 </span>
<span>now we have two equations and two unknowns. I'll use elimination, starting with multiplying the first equation by -3 and the second one by 2. </span>
<span>-6h = -15d + 33 </span>
<span>6h = 14d - 6 </span>
<span>now add both together and you have an equation with one unknown remaining: </span>
<span>0 = -d + 27 </span>
<span>d = 27 </span>
<span>So your answer is 27 stamps. If you want to know how many stamps the others have, you can work back and solve for e and h.</span>
