3 years ago

If (6^0)^x=1 what are the possible values of x

Mathematics

1 answer:

Monica [59]3 years ago

4 0

X could equal 0 or 1

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Simplify <br> (2-4i) -(3 -6i)

SashulF [63]

$2 - 4i - 3 + 6i = - 1 + 2i$

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1 year ago

Use order of operations to make this true 7 11 4 2 = 10

Keith_Richards [23]

Answer:

$7 + 11 - 4 \times 2 = 10$

Step-by-step explanation:

Using order of operations, the first thing to be calculated would be $4 \times 2$ .

That would turn our equation into this:

$7 + 11 - 8 = 10$

You can then calculate left-to-right as usual to get the answer 10.

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3 years ago

What is the value of 0.34×9.

anastassius [24]

The answer is 3.06

0.34

x 9

_________

3.06 Just multiply 0.34*9=3.06 then count two places left to place the decimal point in the proper place

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3 years ago

Read 2 more answers

Read carefully and choose the name of the student who made the correct statement ..... HELPPP hurry

vladimir2022 [97]

Answer:

vince i think

6 0

3 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken to estimate

Hitman42 [59]

Answer:

The minimum sample size is n = 75 so that the desired margin of error is 5 or less.

Step-by-step explanation:

We are given the following in the question:

Population variance = 484

Standard deviation =

$\sigma^2 = 484\\\sigma =\sqrt{484} = 22$

Confidence level = 0.95

Significance level = 0.05

Margin of error = 5

Formula:

Margin of error =

$E = z\times \dfrac{\sigma}{\sqrt{n}}\\\\n = (\dfrac{z\times \sigma}{E})^2$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get

$E\leq 5\\\\1.96\times \dfrac{22}{\sqrt{n}} \leq 5\\\\\sqrt{n} \geq 1.96\times \dfrac{22}{5}\\\\n \geq (1.96\times \dfrac{22}{5})^2\\\\n \geq 74.373$

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.

3 0

2 years ago