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sp2606 [1]
3 years ago
8

¿Cuál es el mínimo común múltiplo de 36, 48 y 72?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

144

Step-by-step explanation:

Multiples of 36:

36, 72, 108, 144, 180, 216

Multiples of 48:

48, 96, 144, 192, 240

Multiples of 72:

72, 144, 216, 288

Therefore,

LCM(36, 48, 72) = 144

Hope this helps!

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There're some old video games you sell on Ebay for $6, $7 and $9. The titles include " The Pirates", "Under the sea" and "The dr
aniked [119]

Answer:

2/9

Step-by-step explanation:

We have 3 video games

I will assume that pirates have a water theme, so 2 have a water theme

That leaves 1 game with no water theme

P (no water theme) = games with no water theme/ total

                                =1/3

The games are 6 7 and 9 dollars

2 games are at least 7 dollars

P( at least 7 dollars) = games at least 7/ total

                                =2/3

P ( no water theme at least 7 dollars) = P (no water theme) * P( at least 7 dollars)

= 1/3*2/3

 = 2/9

6 0
3 years ago
Read 2 more answers
Abby took an 8-question multiple-choice quiz. Suppose
Alenkasestr [34]
It is 0.0623 hope it helps
4 0
3 years ago
What is the y cordinate of the solution<br>solve 8 and 9<br>​
Flauer [41]

Answer:

8) The y coordinate of the solution: 4

9) Average of change from x = 2 to x = 4: 11

Step-by-step explanation:

8)

y = 2x + 2

y = x^2 + 3

So

x^2 + 3 = 2x + 2

x^2 - 2x + 3 - 2 = 0

x^2 - 2x + 1 = 0

(x - 1)^2 = 0

x - 1 = 0

x = 1

Plug in x = 1 into either those 2 equations to find y

y = 2(1) + 2 = 4

or

y = (1)^2 +  3 = 1 + 3 = 4

Answer:

The y coordinate of the solution is 4

9)

p(x) = x^2 + 5x - 2

p(2) = 2^2 + 5(2) - 2 = 4 + 10 - 2 = 12

p(4) = 4^2 + 5(4) - 2 = 16 + 20 - 2 = 34

Average of change from x = 2 to x = 4:

[p(4) - p(2)]/[(x(4) - x(2)] = (34 - 12)/(4-2) = 22 /2 = 11

Answer:

Average of change from x = 2 to x = 4 :11

4 0
3 years ago
Subtract 5x^2 – 2x – 5 from – 2x^2<br> - 5x - 7
user100 [1]

Answer:

-7x^{2} -3x-2

Step-by-step explanation:

(-2x^2-5x-7) - (5x^2-2x-5)\\\\-2x^2 - 5x^2  = -7 x^2\\-5x - -2x = -3x\\-7 - -5 = -2 \\Result: -7x^2-3x-2

3 0
3 years ago
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Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

⇒ \frac{15}{Sin 29} = \frac{20}{sin B}

Using value of sin 29°

⇒ \frac{15}{0.49} = \frac{20}{sin B}

Cross multiplying both side.

⇒ Sin B= \frac{20\times 0.49}{15} = 0.65

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ 29+41+B= 180

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

7 0
3 years ago
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