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Natali5045456 [20]
3 years ago
10

I have no clue how to do this. I just need to pass my online math class.

Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0
So, if you're trying to find the value of f(3), you substitute x=3 into the equation. However, you must be careful.


Which equation in the function do you substitute it into?

2x-9 or 4-x?

You would substitute x=3 into 2x-9.

Why?

See the inequalities at the end of each equation? Those tell you which values you substitute into the equation. Since x=3, you find which inequality it fits under.

It's not x>3 because 3 is not greater than 3. It would be x≤3 because 3 is a value less than or EQUAL to 3.

Now substitute the value x=3 into the correct equation.

2x-9
2(3)-9
6-9
-3

Therefore f(3) = -3.
Lerok [7]3 years ago
3 0
If F(3) then 3=x. So all you would do is substitute 3 in for x
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A closed container has 7.05 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10-24 grams. Which of the following shows
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Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
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xe^y+4\ln y=x^2

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Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method
antoniya [11.8K]

Answer:

a

The estimate is  - 0.0265\le  K \le  0.0465

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is  n_1 = 400

The number of faulty breaks of method A is  X_1 = 32

 The number of microchips broken in method B is  n_2  = 400

 The number of faulty breaks of method A is  X_2 = 32

  The proportion of the faulty breaks to the total breaks in method A is

       p_1 = \frac{32}{400}

      p_1 = 0.08

 The proportion of the faulty to the total breaks in method B is

      p_2 =  \frac{28}{400}

     p_2 =  0.07

For this estimation the standard error is  

      SE =  \sqrt{ \frac{p_1 (1 - p_1)}{n_1}  + \frac{p_2 (1- p_2 )}{n_2} } }

  substituting values

       SE =  \sqrt{ \frac{0.08 (1 - 0.08)}{400}  + \frac{0.07 (1- 0.07 )}{400} } }

      SE = 0.0186

The z-values of confidence coefficient of 0.95 from the z-table is  

       z_{0.95} =  1.96

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

        K = [p_1 - p_2 ] \pm z_{0.95} * SE

substituting values

        K = [0.08 - 0.07 ] \pm 1.96 *0.0186

         K  =  - 0.0265 \ or  \ K  =  0.0465

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is  

      - 0.0265\le  K \le  0.0465

3 0
3 years ago
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