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3 years ago

I have no clue how to do this. I just need to pass my online math class.

Mathematics

2 answers:

Gennadij [26K]3 years ago

8 0

So, if you're trying to find the value of f(3), you substitute x=3 into the equation. However, you must be careful.

Which equation in the function do you substitute it into?

2x-9 or 4-x?

You would substitute x=3 into 2x-9.

Why?

See the inequalities at the end of each equation? Those tell you which values you substitute into the equation. Since x=3, you find which inequality it fits under.

It's not x>3 because 3 is not greater than 3. It would be x≤3 because 3 is a value less than or EQUAL to 3.

Now substitute the value x=3 into the correct equation.

2x-9
2(3)-9
6-9
-3

Therefore f(3) = -3.

Lerok [7]3 years ago

3 0

If F(3) then 3=x. So all you would do is substitute 3 in for x

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Answer:

Step-by-step explanation:

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3 years ago

Answers? Or a hint please I’m begging

olga2289 [7]

Hmm I would say x=q
Hope this helps u <3

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3 years ago

I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS

Damm [24]

Answer:

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3 years ago

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salantis [7]

Answer:

252

Step-by-step explanation:

Split up the shape

First part:

12*12=144

Second part:

((12+(12-6))/2)*24-12

((12+6)/2)*12

18/2*12

9*12 = 108

Total:

108+144 = 252

<u>Plz mark brainliest if this was helpful</u>

8 0

3 years ago

Alyze the following special produ

Eddi Din [679]

Answer:

1) Solving the term $(3x + 5)(2x - 3)$ using F.O.I.L we get $\mathbf{6x^2+x-15}$

2) solving the term $(x + 2)(x - 13)$ using F.O.I.L we get $\mathbf{x^2-11x-26}$

3) Solving $(x+5)^2$ using square of binomial we get $\mathbf{x^2+10x+25}$

4) Solving $(x+5)^2$ using square of binomial we get $\mathbf{x^2-6x+9}$

Step-by-step explanation:

1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have $(3x + 5)(2x - 3)$

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

$(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15$

So, solving the term $(3x + 5)(2x - 3)$ using F.O.I.L we get $\mathbf{6x^2+x-15}$

2) (x + 2)(x – 13). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have $(x + 2)(x -13)$

First: x(x)

Outer: x(-13)

Inner: 2(x)

Last: 2(-13)

Solving we get:

$(x + 2)(x - 13)\\=x(x)+x(-13)+2(x)+2(-13)\\=x^2-13x+2x-26\\=x^2-11x-26$

So, solving the term $(x + 2)(x - 13)$ using F.O.I.L we get $\mathbf{x^2-11x-26}$

3) (x + 5)^2. Solve using the square of Binomial.

The square of binomial is: $(a+b)^2=a^2+2ab+b^2$

Solving:

$(x+5)^2\\=(x)^2+2(x)(5)+(5)^2\\=x^2+10x+25$

So, solving $(x+5)^2$ using square of binomial we get $\mathbf{x^2+10x+25}$

4) (x -3)^2. Solve using the square of Binomial.

The square of binomial used is: $(a-b)^2=a^2-2ab+b^2$

Solving:

$(x-3)^2\\=(x)^2-2(x)(3)+(3)^2\\=x^2-6x+9$

So, solving $(x+5)^2$ using square of binomial we get $\mathbf{x^2-6x+9}$

5 0

2 years ago