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3 years ago

What is he product of (n-8)(n+2)

Mathematics

1 answer:

liubo4ka [24]3 years ago

5 0

Answer:

$\large\boxed{(n-8)(n+2)=n^2-6n-16}$

Step-by-step explanation:

Use FOIL:

We have:

$(n-8)(n+2)=(n)(n)+(n)(2)+(-8)(n)+(-8)(2)=n^2+2n-8n-16$

<em>combine like terms</em>

$=n^2+(2n-8n)-16=n^2-6n-16$

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Step-by-step explanation:

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3 years ago

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pav-90 [236]

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Step-by-step explanation:

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