Question

What is he product of (n-8)(n+2)

Answer 1

Answer:

$\large\boxed{(n-8)(n+2)=n^2-6n-16}$

Step-by-step explanation:

Use FOIL:

(a + b)(c + d) = ac + ad + bc + bd

We have:

$(n-8)(n+2)=(n)(n)+(n)(2)+(-8)(n)+(-8)(2)=n^2+2n-8n-16$

combine like terms

$=n^2+(2n-8n)-16=n^2-6n-16$