Answer:
11/20
Step-by-step explanation:
I turned them in to improper fractions, divided, then simplified
Step-by-step explanation:
Let the number be x.
ATQ,
Malachy halves the number and gets an answer of 67.3.
This the equation for the given statement.
It can also be written as :
Hence, this is the required solution.
So g(x) doesn't come in
ok
remember pemdas
inside first
evaluate f(4)
f(4)=4^2+1=16+1=17
now we have
[17]^2=289
answer s 289
18 divided by 30 is 0.6. So I would say that B, or 0.6, is the correct answer.
Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft