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4 years ago

Function or no function? Why

Mathematics

1 answer:

Kitty [74]4 years ago

5 0

Answer:

It is not a Function

Step-by-step explanation:

There are multiple x-values that are repeating in the relation. If we did the vertical line test, it will fail because the line would touch two parts of the graph.

The relation is not a function.

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Calculate the circumference of the circle. Use 3.14 for pi. I WILL MARK BRAINLIEST

Harrizon [31]

Answer:

The answer would be B

Step-by-step explanation:

C=2(pi)r

C=25.12

8 0

3 years ago

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The graphs of functions f(x) and g(x) = f(x) + k are shown below what is the value of k?

natali 33 [55]

Answer:

k = 2

Step-by-step explanation:

f(x) and g(x) = f(x) + k

G(x) is the function f(x) moved up k units

G(x) is moved up 2 units so k is 2

5 0

3 years ago

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Someone plz help me I need help

trasher [3.6K]

This isnt clear enough please explain

8 0

3 years ago

X over 16 equals 6 over 24

AlekseyPX

Answer: x=4 *The answer should be the positive sign.*

Step-by-step explanation:

cancel by the common factor of 6.

x/16=1/4

multiply by 16 both sides of an equation.

16x/16=1*16/4

multiply the numbers.

1*16=16

=16/4

16/4=4

x=4

Hope this helps!

Thanks!

Have a great day!

4 0

4 years ago

Write an exponential function y = abx for a graph that includes (–3, 16) and (–1, 4) f(x) = 2(0.5)x f(x) = 0.5(2)x f(x) = 4(0.3)

Arisa [49]

Answer: $f(x)=2(0.5)^x$

Step-by-step explanation:

Given, the exponential function $y = ab^x$ for a graph that includes (–3, 16) and (–1, 4).

On putting these points, we will have

$f(-3)=16=ab^{-3}\\\\ f(-1)=4=ab^{-1}$

Now,

$\dfrac{f(-3)}{f(-1)}=\dfrac{16}{4}=\dfrac{ab^{-3}}{ab^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b^{-3}}{b^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b}{b^3}=\dfrac{1}{b^2}\\\\\Rightarrow\ b^2=\dfrac{1}{4}\\\\\Rightarrow\ b=\pm\dfrac{1}{2}=\pm0.5$

since the multiplicative factor cannot be negative, so b= 0.5.

At b= 0.5

$4=a(0.5)^{-1}\\\\\Rightarrow\ 4=a(\dfrac{1}{2})^{-1}\\\\\Rightarrow\ 4=a(2)\\\\\Rightarrow \ a=2$

So, the required function is $f(x)=2(0.5)^x$ .

3 0

4 years ago