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2 years ago

Waves transport _______ over distances.

Mathematics

2 answers:

Degger [83]2 years ago

8 0

Waves transport energy over distances.

Hope I helped! ( Smiles )

Virty [35]2 years ago

5 0

The answer is energy

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Name the parts of the expression then, write it in expanded form. a. 14b b.30jk

Makovka662 [10]

Answer:

a. 14 is a coefficient, and b is a variable.

This can be expanded to 14*b

b. 30 is a coefficient, and j and k are variables.

This can be expanded to 30*j*k

3 0

2 years ago

Which statement is true?

Dafna1 [17]

The second one is the true statement

7 0

2 years ago

An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan

AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X= $x_{0}$ ]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0

2 years ago

X^2 - y^2 = 100

luda_lava [24]

Answer:

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

$x+y=5$

Subtract y from both sides:

$x=5-y$

Now, substitute "5-y" for "x" in the first equation:

$(5-y)^2-y^2=100$

Note that:

$(a-b)^2=a^2-2ab+b^2$

$25-10y+y^2-y^2=100$

Cancel out like terms:

$25-10y=100$

Subtract 25 from both sides:

$-10y=75$

Divide both sides by -10

$y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}$

Now, substitute this value back into either of the equations to solve for x.

$x+y=5\\x-\frac{15}{2}=5\\$

Add 15/2 to both sides:

$x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}$

Now, find the difference:

$x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20$

8 0

2 years ago

PLEASE HELP ME ANSWER THIS!! THANK YOU

jeka94

Answer:

1. There are 609 more fiction books than non-fiction books in the library

2. Cheryl had $900 initially

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2 years ago