Question

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi. someone pls help me

Answer 1

Answer:

10 inches

Step-by-step explanation:

Given:

Area of pizza = 78.5 in²

To find:

Minimum width of placement to be placed underneath the pizza so that it does not touch the table?

Solution:

We are actually required to find out the diameter of the circular pizza here.

That will be the minimum width of the placement to be placed underneath the pizza so that pizza does not touch the table.

Let us have a look at the formula of area of a circle.

$A=\pi r^2$

Where $r$ is the radius of the circle

We are given that

$A = 78.5\ in^2$

$\Rightarrow 78.5 = \pi r^2\\\Rightarrow 78.5 = 3.14\times r^2\\\Rightarrow \dfrac{78.5}{3.14} = r^2\\\Rightarrow r^2=25\\\Rightarrow r =5\ in$

Now, we know that the diameter is given as twice of the radius.

So, minimum width required = Diameter = 2 $\times$ 5 = 10 inches