The most simplified meaning within a language is MORPHEME.
In English language, a morpheme refers to a language unit, that is made up of a word or a word elements which can not be further broken down into meaningful smaller parts. Morphemes are the smallest, basic, grammatical unit of a language that have distinct meaning, just as atoms are the smallest unit of elements in chemistry. Examples of morphemes are: sad, joy, depress, excited, etc.
Answer:
373.88 torr
Explanation:
P1 = 350 torr
T1 = 20°C = (20 + 273.15)K = 293.15K
P2 = ?
T2 = 40°C = (40 + 273.15)K = 313.15K
From pressure law,
Pressure of a given mass of gas is directly proportional to its temperature.
P = KT
K = P / T
P1 / T1 = P2 / T2
Solve for P2
P2 = (P1 * T2) / T1
P2 = (350 * 313.15) / 293.15
P2 = 109602.5 / 293.15
P2 = 373.878 torr
P2 = 373.88 torr
The new pressure of the gas would be 373.88 torr.
For very large numbers, it is much more convenient to use scientific notation. To do this, detect first the position of the decimal point. For whole numbers, the decimal point is place implicitly after the very last digit. Then, move this decimal point to the left until you reach to the last digit. In this case, you moved 8 places until you reach 6.4. Because the number is more than 1, the exponent would have a positive sign. Hence, the scientific notation would be 6.4×10⁸.
Answer:
Average atomic mass = 85.557 amu.
Explanation:
Given data:
Percent abundance of Rb-85 = 72.15%
Percent abundance of Rb-87 = 27.85%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (72.15×85)+(27.85×87) /100
Average atomic mass = 6132.75 + 2422.95 / 100
Average atomic mass = 8555.7 / 100
Average atomic mass = 85.557 amu.
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