The volume of NaOH required is 0.08 dm³
To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:
H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O
From the balanced equation above,
Mole ratio of the acid, H₂SO₄
Mole ratio of the base, NaOH 
Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:
Molarity of the base, NaOH 
Volume of the acid, H₂SO₄ 
Molarity of the acid, H₂SO₄ 
<h3>Volume of the base, NaOH

=? </h3>

Cross multiply

Divide both side by 0.505

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

Therefore, the volume of NaOH required is 0.08 dm³
Learn more: brainly.com/question/19053582