Answer:
101.98 L
Explanation:
Ideal Gas Law PV = n R T R = gas constant = .082057 L-atm/mol-K
6.35 (V) = 4 * .082057 * 1973
V = 101.98 L
You forgot one...and that happens to be the answer---> Accuracy
Answer:
Explanation:
The chemical equation for the reaction is :
The standard enthalpy of formation of the above equation is as follows:
= -1274.4 kJ/mol
= -277.7 kJ/mol
= -393.5 kJ/mol
where ;
= stochiometric coefficients of products
stochiometric coefficients of reactants
= formation standard enthalpy of products
= formation standard enthalpy of reactants
For ;
The standard enthalpy of formation of of the reactant and the products are :
The is as follows:
(to kJ/K)
Given that;
at T = 25°C = ( 25 + 273) K = 298 K
As is negative; the reaction is spontaneous
= negative
= positive; Therefore , the reaction is spontaneous at all temperature , We can then say that the spontaneity of this reaction is dependent on temperature.
Ca(OH)2 -------> CaO + H2O
ratio is 1 : 1
CaO Mr= 56g
15/56 = 0.268 mol (mols of CaO in 15g)
Ca(OH)2 Mr= 74g
0.268x74= 19.83g (required amount of Cash(OH)2)
Answer:
3.76 g of O₂ are needed to produced 12.5 g of Fe₂O₃
Explanation:
The reaction is: 4Fe (s) + 3O₂ (g) → 2Fe₂O₃ (s)
4 moles of iron react to 3 moles of oxygen in order to produce 2 moles of iron (III) oxide.
Let's determine the moles of the produced product.
12.5 g . 1mol/ 159.69g = 0.0783 moles
If we assume Iron in excess, we work with the oxygen.
2 moles of Fe₂O₃ are produced by 3 moles of oxygen
Then, 0.0783 moles of Fe₂O₃ might be produced by (0.0783 . 3)/2
0.117 moles.
We convert the moles to mass → 0.117 mol . 32 g/1mol = 3.76 g