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fgiga [73]
3 years ago
7

Explain the process of fading of a carpet upon repeated exposure to sunlight?

Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

<em>it is a chemical change as there is a change in color</em>

Explanation:

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Gre4nikov [31]
Most atoms have more neutrons than protons which accounts for basically half of the nucleuses mass.
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3 years ago
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How many grams in 6.20 x 10^25 atoms of bromine (Br) ? image attached , will give brainliest
Deffense [45]

Answer:

8239.2g

Explanation:

Given parameters:

Number of atoms in Br  = 6.2 x 10²⁵atoms

Unknown:

Mass of Br = ?

Solution:

From mole concepts, we know that:

       1 mole of a substance contains 6.02 x 10²³ atoms/mol

 Molar mass of Br  = 80g/mol

6.2 x 10²⁵atoms  x \frac{1}{6.02 x 10^{23} } \frac{mol}{atoms} x  80 x \frac{g}{moles}  

          = 8239.2g

8 0
3 years ago
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
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When the experiment was carried out, the temperature was 22 oC and atmospheric pressure was 1.007 atm. Using the Ideal Gas Law a
lesantik [10]

Answer:

number of moles of H_2=4.16mol

Explanation:

experiment data:

temperature= 22^{\circ}C=273+22 k=295k

pressure=1.007 atm

volume is missing so assuming volume-=100L

using ideal law relationship

ideal gas means gas which occupies negligible space and there is no interaction between the molecules of gases.

PV=nRT

put all the experimental data, we get

n=4.15 mol

number of moles of H_2=4.16mol

4 0
3 years ago
Some chemical reactions take a very long time to go to completion or cannot be directly measured. Which law allows one to use tw
katrin2010 [14]

Answer:

D

Explanation:

If you add two or more thermochemical equations to give a final equation, then you also add the heats of reaction to give the final heat of reaction

7 0
3 years ago
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