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Natalka [10]
3 years ago
15

How many valence electrons in Al(OH)4-

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

Answer: There is 1 valence electron in Al(OH)4-

Explanation:

The valence electrons are the electrons that are present in the outer shell of an atom.

In this case, the "Al" works with 3 electrons of valence, while the "OH-" has only 1 electron of valence, however we have 4 atoms of "OH-", in this case, the OH- donates a lone pair of atoms to make the covalent bonds with the "Al"  but  kind of weak, that is why , usually this molecule has special conditions to be formed, like high pH, where the negative state remain longer.

Softa [21]3 years ago
4 0
<h2>Answer:</h2>

There is only one valence electron in  Al(OH)4- anion.

<h3>Explanation:</h3>
  • Valency is the number of electrons in the outer most shell of an atom.
  • In this compound, aluminium has the valency of +3. It means Al needs only 3 electrons to complete its outer most shell.
  • Hence the stable molecule Al(OH)3.
  • But the addition of one another OH- leads to the negative charge and there is one spare electron which can make bond to an atom to stable the compound.
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3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

4 0
3 years ago
What are the laws of Newton?
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an object that is at rest will stay at rest inless a force acts upon it.

An oject that is in motion will not change its velocity unless a force acts upon it.

4 0
3 years ago
Read 2 more answers
In a single displacement reaction between sodium phosphate and barium, how much of each product (in grams) will be formed from 1
weeeeeb [17]

Answer:

A. 3.36g of Na.

B. 14.62g of Ba3(PO4)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Ba + 2Na3PO4 → 6Na + Ba3(PO4)2

Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.

This is illustrated below:

Molar Mass of Ba = 137g/mol

Mass of Ba from the balanced equation = 3 x 137 = 411g

Molar mass of Na = 23g/mol

Mass of Na from the balanced equation = 6 x 23 = 138g

Molar mass of Ba3(PO4)2 = (3 x 137) + 2[31 + (4x16)] = 411 + 2[31 + 64] = 601g/mol

Mass of Ba3(PO4)2 from the balanced equation = 1 x 601 = 601g

Summary:

From the balanced equation above,

411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.

A. Determination of the mass of Na produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 138g of Na.

Therefore, 10g of Ba will react to produce = (10 x 138)/411 = 3.36g of Na.

Therefore, 3.36g of Na is produced.

B. Determination of the mass of Ba3(PO4)2 produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 601g of Ba3(PO4)2.

Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.

Therefore, 14.62g of Ba3(PO4)2 is produced.

7 0
3 years ago
Which of the following is not a characteristic of reliable science?
natta225 [31]

Answer:

Paid sponsorship by a company.

Hope this helps! :)

4 0
3 years ago
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