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3 years ago

How many valence electrons in Al(OH)4-

Chemistry

2 answers:

Amanda [17]3 years ago

7 0

Answer: There is 1 valence electron in Al(OH)4-

Explanation:

The valence electrons are the electrons that are present in the outer shell of an atom.

In this case, the "Al" works with 3 electrons of valence, while the "OH-" has only 1 electron of valence, however we have 4 atoms of "OH-", in this case, the OH- donates a lone pair of atoms to make the covalent bonds with the "Al" but kind of weak, that is why , usually this molecule has special conditions to be formed, like high pH, where the negative state remain longer.

Softa [21]3 years ago

4 0

<h2>Answer:</h2>

There is only one valence electron in Al(OH)4- anion.

<h3>Explanation:</h3>

Valency is the number of electrons in the outer most shell of an atom.
In this compound, aluminium has the valency of +3. It means Al needs only 3 electrons to complete its outer most shell.
Hence the stable molecule Al(OH)3.
But the addition of one another OH- leads to the negative charge and there is one spare electron which can make bond to an atom to stable the compound.

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How to solve x² in differential

g100num [7]

Answer:

x² = mutiphy by them self

Explanation:

4 0

3 years ago

A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o

statuscvo [17]

<u>Answer:</u> The value of $K_{eq}$ is 0.044

<u>Explanation:</u>

We are given:

Initial moles of methane = $4.10\times 10^{-2}mol=0.0410moles$

Initial moles of carbon tetrachloride = $6.51\times 10^{-2}mol=0.0651moles$

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of methane = $\frac{0.0410}{1.00}=0.0410M$

Concentration of carbon tetrachloride = $\frac{0.0651}{1.00}=0.0651M$

The given chemical equation follows:

$CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)$

<u>Initial:</u> 0.0410 0.0651

<u>At eqllm:</u> 0.0410-x 0.0651-x 2x

We are given:

Equilibrium concentration of carbon tetrachloride = $6.02\times 10^{-2}M=0.0602M$

Evaluating the value of 'x', we get:

$\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M$

Now, equilibrium concentration of methane = $0.0410-x=[0.0410-0.0049]=0.0361M$

Equilibrium concentration of $CH_2Cl_2=2x=[2\times 0.0049]=0.0098M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044$

Hence, the value of $K_{eq}$ is 0.044

8 0

3 years ago

How to do dots and cross diagrams

Likurg_2 [28]

Answer:

Draw circles to represent the electron shell of each atom overlapping the circles where the atoms are bonded. Add dots to represent the outer electrons of one type of atom (H). Add crosses to represent the outer electrons of the other type of atom (Cl). Make sure the electrons are always in pairs.

6 0

3 years ago

PLEASE HELP ASAP

erma4kov [3.2K]

In the so called rain shadow effect we have interaction between all of the four major Earth spheres. When we have a coastal region where there's a high mountain range, the part of the mountain that is facing the sea will differ a lot from the part of the mountain that is on the other side. The water from the sea evaporates. The water vapor makes the air wet. The warm and wet air masses from the sea will come to the coastline, once they reach the mountain they will start to accumulate as they can not pass through it. As they accumulate rainfall appears. The rainfall contributes to a lush vegetation on this side of the mountain (windward side). The rain shadow effect appears on the leeward side of the mountain, and it mostly gets dry, strong, downward winds. These conditions result in drier climate, much less vegetation, and much increased erosion. Thus we can easily see that we have in this case interaction between the hydrosphere (the sea and the rainfall), the geosphere (the ground, soil, rocks), biosphere (the vegetation), and atmosphere (the winds, the clouds).

6 0

4 years ago

How many molecules are present in 4.21 moles of HBr?

salantis [7]

Answer:

The answer is

<h3>2.53 × 10²⁴ molecules</h3>

Explanation:

The number of molecules present can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

<h3>2.53 × 10²⁴ molecules</h3>

Hope this helps you

6 0

3 years ago