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Natalka [10]
3 years ago
15

How many valence electrons in Al(OH)4-

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

Answer: There is 1 valence electron in Al(OH)4-

Explanation:

The valence electrons are the electrons that are present in the outer shell of an atom.

In this case, the "Al" works with 3 electrons of valence, while the "OH-" has only 1 electron of valence, however we have 4 atoms of "OH-", in this case, the OH- donates a lone pair of atoms to make the covalent bonds with the "Al"  but  kind of weak, that is why , usually this molecule has special conditions to be formed, like high pH, where the negative state remain longer.

Softa [21]3 years ago
4 0
<h2>Answer:</h2>

There is only one valence electron in  Al(OH)4- anion.

<h3>Explanation:</h3>
  • Valency is the number of electrons in the outer most shell of an atom.
  • In this compound, aluminium has the valency of +3. It means Al needs only 3 electrons to complete its outer most shell.
  • Hence the stable molecule Al(OH)3.
  • But the addition of one another OH- leads to the negative charge and there is one spare electron which can make bond to an atom to stable the compound.
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I assume your talking about carbon when you say 12 so it'd be 12 grams if you are

Explanation:

The molar mass of any substance in grams per mole is numerically equal to the mass of that substance expressed in atomic mass units.

Hope this helps you some

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Which refers to solid ice that condenses and forms on surfaces like grass or windows?
ohaa [14]
Frost is your answer
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Consider the following numbered processes: 1. A → 2B 2. B → C + D 3. E → 2D ΔH for the process A → 2C + E is
aivan3 [116]

Answer:

ΔH = ΔH₁ + ΔH₂ - ΔH₃

Explanation:

Given that:

1. A → 2B

2. B → C + D

3. E → 2D

Assuming from the corresponding ΔH for process 1, 2 and 3 are ΔH₁, ΔH₂, ΔH₃ respectively.

To estimate the ΔH for the process A → 2C + E

We multiply 2 with equation 2 where (B → C + D)

2B → 2C + 2D ⇒ 2ΔH₂

Also, let's switch equation (3), such that we have,

2D → E -ΔH₃

The summation of all the equation result into :

A → 2C + E

where; ΔH = ΔH₁ + ΔH₂ - ΔH₃

6 0
3 years ago
what the type of solid materials are typically hard, have high melting pionts and poor electrical conductivities​
Virty [35]

Answer:

Ionic solids

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7 0
3 years ago
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Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 3
stealth61 [152]

This is an exercise in<u> the General Combined Gas Law</u>.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • V₁ = 4.00 l
  • P₁ = 365 mmHg
  • T₁ = 20 °C + 273 = 293 K
  • V₂ = 2,80 l
  • T₂ = 30 °C + 273 = 303 K
  • P₂ = ¿?

We apply the following formula:

  • P₁V₁T₂=P₂V₂T₁     ⇒  General formula

Where:

  • P₁=Initial pressure
  • V₁=Initial volume
  • T₂=end temperature
  • P₂=end pressure
  • T₂=end temperature
  • V₁=Initial temperature

We clear for final pressure (P2)

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}

We substitute our data into the formula:

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})}  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 }  \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}

Answer: The new canister pressure is 539.224 mmHg.

<h2>{ Pisces04 }</h2>
6 0
2 years ago
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