Mac and Keena are experimenting with pulses on a rope. Mac vibrates one end up and down while Keena holds the other end. This creates a pulse which they observe moving from end to end. How does the position of a point on the rope before the start of the pulse compare to its position after the pulse passes? Explain your reasoning.
Potholder should have high insulation and low conductivity, therefore the correct answer is the option B
<h3>What is insulation?</h3>
Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.
For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.
The ability of an electric charge or heat to pass through a material is measured by its conductivity. A material is considered a conductor if it offers very little resistance to the flow of thermal or electric energy.
Thus, Potholders should be highly insulated and have low conductivity, therefore the correct answer is the option B
Learn more about insulation from here
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your question seems incomplete, the complete question is
To be effective, a pot holder should have low _____. viscosity conductivity malleability density
Answer: a) 6.7 ; b) -9.5 * 10^-7 C induced in the dielectric on the positive plate and 9.5 * 10^-7 C induced in the other side of the dielectric close to the negative plate.
Explanation: In order to solve this problem we have to use the formule for two parallel plates capacitor, which is given by:
C= εo*A/d where A and d are the cross section and separation of the plates, respectively.
Aditionally we know that C= Q/ΔV and ΔV = E*d
By uning both expression we have:
C= εo*A/d=Q/ΔV=εo*A/d=Q/E*d then
with a dielectric between the plates, the new C is obtained by multiply by k the initial capacitance.
finally we have
εo*k*A=Q/E
then k= Q/(E*εo*A)= 6.7
In the dielectric is induced oposite charge to each plate of the capacitor, The value of induced charge in the dielectric is the same for the capacitor but with oposite sign.
<span>We are using the formula: v = rω
Please consider that they have the same tangential velocity at their edges.
Therefore we can equate: r1 ω1 = r2 ω2
And re-arrange: ω1 / ω2 = r2 / r1</span>
Answer:
the super train is not completely within the tunnel.
Explanation:
From the given information:
The proper length = 1200 ft
The super train speed = 0.99c
By applying the concept of length contraction, the contracted length of the super-train can be determined by using the formula:
L = 169.3 ft
≅ 169 ft
Thus, the contracted length is 169 ft more than the proper length of the tunnel L' 50 ft.
As such, the super train is not completely within the tunnel.