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balandron [24]
3 years ago
14

How much heat is required to increase the temperature of 100.0 grams of iron from 15.0oC to 40.2oC? (The specific heat of iron i

s 0.46 J/g xoC)
Physics
2 answers:
Lesechka [4]3 years ago
7 0
The heat required to increase temp is 1150 j
Mashutka [201]3 years ago
7 0
You are given the initail and final temperature of the substance which is 15°C and 40°C with a mass of iron of 100 grams. Also the specific heat of iron is 0.46 J/g°C. You have to use the formula Q = mcpΔT to find the heat, Q, cp (specific heat of substance) and ΔT the change in temperature.
<span>
Q = </span>mcpΔT
Q = 100*0.46*(40 - 15)
Q = 1150J
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What is the acceleration of the object?<br> m/s²
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Answer:

-2.5m/s^2

Explanation:

10-40/12-0=-2.5

7 0
2 years ago
Water has a mass per mole of 18.0 g/mol, and each water mo- lecule (H2O) has 10 electrons. (a) How many electrons are there in o
Dovator [93]

Answer:

a) There are 3,35*10^{26} electrons in a liter of water.

b) The net charge is -53601707,1 C

Explanation:

a) To find out how many electrons are in a liter of water (equivalent to 1000 grams of water), we have to find out how many molecules of water there are and then multiply it by 10 (e- per molecule).

We can find out how many molecules are by finding the number of moles and then multiplying it by Avogadro's number (number of elements per mol):

e^{-}= \frac{m_{water} }{M_{water} } * Avogadro* \frac{e^{-} }{molecule}=  \frac{1000g }{18g/mol} * 6,022*10^{23} * \frac{10e^{-} }{molecule}=3,35*10^{26} e^{-}

b) As all electrons have the same charge, in order to find the net charge of those electrons we have to multiply the charge of a single electron by the number of electrons:

Net charge= -1,602*10^{-19}  \frac{C}{e^{-} }  *3,35*10^{26} e^{-}=-53601707,1 C

An important clarification is that while the net charge may seem huge, water as a whole is a neutral medium, because there are as many protons as there are electrons, and as they have the same charge, the net charge of water is 0.

8 0
4 years ago
The two general types of air pollution are _____ and _____.
WARRIOR [948]

Answer:

The two general types of air pollution are _____ and _____.

answer: gases and particles

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5 0
3 years ago
Read 2 more answers
A 91 kg zebra is traveling 7 m/s east. What is the zebra’s momentum? kg-m/s
frez [133]
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5 0
3 years ago
The isotope 23893Np has a half-life of 2.0 days. If 4.00 grams are produced at noon on Monday, what will be the mass of neptuniu
viva [34]

Answer:

0.25 gram of neptunium is remaining

Explanation:

First we calculate the no. of half lives passed. For that we have formula:

n = t/T

where,

n = no. of half lives passed = ?

t = total time passed = 8 days (From Monday noon to Tuesday noon of following week)

T = Half Life Period = 2 days

Therefore,

n = 8 days/2 days

n = 4

Now, for the remaining mass of neptunium, we use the formula:

m = (mi)/(2)^n

where,

mi = initial mass of neptunium = 4.00 grams

m = remaining mass of neptunium = ?

Therefore,

m = 4 grams/2⁴

<u>m = 0.25 gram</u>

3 0
3 years ago
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