Answer:
Explanation:
From the given information;
Let assume that the distance travelled by the speeder prior to the time the trooper catches with it to be = d
the time interval to be = t
Then, the speeder speed = distance/time
Making distance the subject; then:
distance (d) = speed × time
d = (50 m/s)t
d = 50 t --- (1)
Now, for the trooper; Using the equation of motion:
d = 20t + 1.25t²
Replace the value of d in (1) to the above equation, we have:
50 t = 20 t + 1.25t²
50t - 20t = 1.25t²
30t = 1.25t²
30 = 1.25t
t = 24 seconds
From (1), the distance far down the highway the trooper will travel prior to the time it catches up with the speeder is:
= 50t
= 50(24)
= 1200 seconds
Do you speak a little English cuz I can’t help you if a can’t understand you
Answer:
83,900 J
Explanation:
First, find the acceleration:
F = ma
1150 N = (1600 kg) a
a = 0.719 m/s²
Now find the final velocity.
Given:
Δx = 45.8 m
v₀ = 6.25 m/s
a = 0.719 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)
v = 10.2 m/s
Now find the final KE:
KE = ½ mv²
KE = ½ (1600 kg) (10.2 m/s)²
KE = 83,920 J
Rounded to three significant figures, the final kinetic energy is 83,900 J.
Answer:
The amount of electrons that flow in the given time is 3.0 C.
Explanation:
An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.
i.e I = 
...................(1)
It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.
In the given question, I = 1.5A, t = 2s, find Q.
From equation 1,
Q = I × t
= 1.5 × 2
= 3.0 Coulombs
The amount of electrons that flow in the given time is 3.0 C.
Answer:
B
Explanation:
Depends Mostly on bonds electrolysis can be used, chemical bonding like additional of water or by heating back to their elements.
