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lana66690 [7]
3 years ago
7

What is the ratio of magnitudes of their angular velocities, ω1/ω2? express your answer in terms of the variables r1 and r2?

Physics
1 answer:
kicyunya [14]3 years ago
8 0
<span>We are using the formula: v = rω Please consider that they have the same tangential velocity at their edges. Therefore we can equate: r1 ω1 = r2 ω2 And re-arrange: ω1 / ω2 = r2 / r1</span>
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Estimate the order of magnitude of the length, in
Scrat [10]
A) a mouse, to an order of magnitude = 0.1 m ( a tenth of a meter ) That would be a big mouse but the alternatives are 1 meter or one hundredth of a meter... so go with 1/10th 

<span>b) Easy = 1 meter </span>

<span>c) two choices 10m or 100 m . Go with 100 m </span>

<span>d) Stretch it out , trunk tip to tail tip - call it 10 m </span>

<span>e) Your choice 100 m or 1000 m..... These are estimates. So long as you are within one order of magnitude you can't really be given wrong. So I'd say 100m</span>
8 0
3 years ago
Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
where
\mu_0 is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated

Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
r=40.0 cm=0.40 m, 
which is the distance at which the other wire is located:
B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T

Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N

2) direction of the force: 
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)

Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive

A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
2 years ago
Newton's First Law says that an object at rest will stay at rest, and an object in motion will stay in motion unless:
Verdich [7]

Answer: Acted on by equal forces in opposite direction

Explanation:

Newton's First Law says that every body continue in its state of rest or constant speed on a straight line unless being acted upon by an external force.

6 0
3 years ago
What is a successful result of science
Vlada [557]
I think the answer is discovery.
7 0
2 years ago
Numbered 8 nowwwwwww
amm1812

Torque =  r x F

|F| =  mg =  60 * 10 N = 600 N ( assuming g ~ 10m/s^2)

distance of fulcrum = torque / Force = 90/600 m = .15 m.

7 0
3 years ago
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