Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
I'm assuming this is a Pythagorean theorem problem. If so the answer would be √125
Answer:
x > 10
Step-by-step explanation:
5x - 24 > 26
Add 24 on both sides.
5x -24 + 24 > 26 + 24
5x > 50
Divide by 5 on both sides.
x > 50 ÷ 5
Find x.
x > 10
Answer:
x = -1
Step-by-step explanation:
1. Simplifying
6x + 4 = 4x + 2
2. Reorder the terms
4 + 6x = 4x + 2 to 4 + 6x = 2 + 4x
3. Solving
4 + 6x = 2 + 4x
4. Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right. Then add '-4x' to each side of the equation.
4 + 6x + -4x = 2 + 4x + -4x
5. Combine like terms: 6x + -4x = 2x
4 + 2x = 2 + 4x + -4x
6. Combine like terms: 4x + -4x = 0
4 + 2x = 2 + 0
4 + 2x = 2
7. Add '-4' to each side of the equation.
4 + -4 + 2x = 2 + -4
8. Combine like terms: 4 + -4 = 0
0 + 2x = 2 + -4
2x = 2 + -4
9. Combine like terms: 2 + -4 = -2
2x = -2
10. Divide each side by '2'.
x = -1
11. Simplifying
x = -1
