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3 years ago

PLEASE HELP! WILL GIVE BRAINLIEST!

2 answers:

8 0

Frame of reference refers to something that is not moving with respect to an observer that can be used to detect motion.

tresset_1 [31]3 years ago

6 0

It means to view it in a way where you can understand it, and other people can understand it

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Wheel A has a radius of R and wheel B has a radius of 2R. Wheel A has all the mass at the rim, while wheel B has the mass unifor

azamat

Answer:

Wheel A.

Explanation:

The lesser the moment of inertia, the greater the angular acceleration. Then, the moments of inertia of each wheel are described below:

Wheel A

$I_{A} = M\cdot R^{2}$

Wheel B

$I_{B} = \frac{1}{2}\cdot M \cdot (2\cdot R)^{2}$

$I_{B} = 2\cdot M\cdot R^{2}$

The wheel A accelerates faster in response to the torque.

3 0

3 years ago

Can u help me with C

Vladimir79 [104]

I believe it would be 2m/s.

6 0

4 years ago

Read 2 more answers

. Two people are pushing a car of mass 2000 kg.

Viktor [21]

Answer:

two people who are not going to be able to make it to class today because of the day and then I will be there at the house and then we can go

5 0

4 years ago

Psychological profiling is also known as criminal profiling. True or False?

Nikolay [14]

So my opinion that is false bc. the psychological profiling not is necessary being as criminal profiling ,the criminal mean a greater,intensive word in the way of ,,killer" ,when the ,,psychological" profile is total different way

hope helped

8 0

3 years ago

Read 2 more answers

An assault rifle fires an eight-shot burst in 0.40 s. Each bullet has a mass of 7.5 g and a speed of 300 m/s as it leaves the gu

myrzilka [38]

Answer:

The average recoil force on the gun during that 0.40 s burst is 45 N.

Explanation:

Mass of each bullet, m = 7.5 g = 0.0075 kg

Speed of the bullet, v = 300 m/s

Time, t = 0.4 s

The change in momentum of an object is equal to impulse delivered. So,

$F\times t=mv\\\\F=\dfrac{mv}{t}$

For 8 shot burst, average recoil force on the gun is :

$F=\dfrac{8mv}{t}\\\\F=\dfrac{7.5}{1000}\cdot\dfrac{300}{0.4}\cdot8\\\\F=45\ N$

So, the average recoil force on the gun during that 0.40 s burst is 45 N.

5 0

3 years ago