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GalinKa [24]
3 years ago
13

How much would it cost to operate five incandescent light bulbs for the months of April and May, collectively, given that each b

ulb is one hundred and fifty Watts, electricity for home use is 0.3AED per kilowatt-hour, and that the light s will be on for three hours per day during this two month period.
please i need an answer fast or my teacher will kill me
Physics
1 answer:
const2013 [10]3 years ago
3 0

Answer:

Total Cost is 41.18 AED

Explanation:

Per day number of hours light bulbs were on=3hours

5 bulbs power consumption = 150Wx5 = 750W

Electricity usage per day = 750 x 3 = 2250Wh = 2.25kWh

April has 30 days and May has 31 days. Therefore totals days = 61days

Total power consumption = 2.25x 61 = 137.25kWh

Total Cost = 137.25x 0.30 = 41.175 AED

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3 years ago
Is there any machine that is 100% efficient? why?why not
denis-greek [22]

Answer:

No, it's not there.

Explanation:

For a machine to be 100% efficient, it has to be with an output which is equal to its input. But machines have an out put less than an input, hence efficiency below 100%.

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3 years ago
Does the force of kinetic friction depend on the weight of the block? explain.
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7 0
2 years ago
After a long night of cramming for a test, your college room-mate hits his head forcefully against the wall of your room in desp
zhannawk [14.2K]

Answer: the wall contracts the force exerted by his head. The wall produces the opposite force which is equal to the force his head bangs the wall with.

Explanation: if his head exerts a much greater force than the wall can counteract the wall will be destroyed, if the wall exerts a much greater force than his head exerts he will be pushed far back and might even suffer a broken head.

The wall in this case provides the opposite reactive force.

6 0
3 years ago
A world-class sprinter can burst out of the blocks to essentially top speed (of about 11.5 m/s) in the first 15.0 m of the race.
wolverine [178]
Given:
u = 0, initial speed (sprinter starts from rest)
v = 11.5 m/s, final speed
s = 15 m, distance traveled to attain final speed.

Let
a =  average acceleration,
t = time taken to attain final speed.

Then
v² = u² + 2as
or
(11.5 m/s)² = 2*(a m/s²)*(15 m)
a = 11.5²/(2*15) = 4.408 m/s²

Also
v = u +a t
or
(11.5 m/s) = (4.408 m/s²)*(t s)
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Answer:
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The time required is 2.61 s (nearest hundredth).
8 0
3 years ago
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