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Blababa [14]
4 years ago
11

Your friend is trying to construct a clock for a craft show and asks you for some advice. She has decided to construct the clock

with a pendulum. The pendulum will be a very thin, very light wooden bar with a thin, but heavy, brass ring fastened to one end. The length of the rod is 80 cm and the diameter of the ring is 10 cm. She is planning to drill a hole in the bar to place the axis of rotation 15 cm from one end. She wants you to tell her the period of this pendulum.

Physics
1 answer:
Anastasy [175]4 years ago
4 0

Answer:

The period of the pendulum is  T  =  1.68 \  sec

Explanation:

The diagram illustrating this setup is shown on the first uploaded image

From the question we are told that

     The length of the rod is L =  80 \ cm

       The diameter of the ring is d = 10 \ cm

       The distance of the hole from the one end  D =  15cm

From the diagram we see that point A is the center of the brass ring

 So the length from the axis of  rotation is mathematically evaluated as

          AP = 80 + 10 -5 -15  

          AP =  70 \ cm =  \frac{70}{100}  =  0.7 \ m

Now the period of the pendulum is mathematically represented as

             T  = 2 \pi  \sqrt{\frac{AP}{g} }

             T  =  2 \pi \sqrt{\frac{0.7}{9.8 } }

             T  =  1.68 \  sec

     

     

     

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