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Blababa [14]
3 years ago
11

Your friend is trying to construct a clock for a craft show and asks you for some advice. She has decided to construct the clock

with a pendulum. The pendulum will be a very thin, very light wooden bar with a thin, but heavy, brass ring fastened to one end. The length of the rod is 80 cm and the diameter of the ring is 10 cm. She is planning to drill a hole in the bar to place the axis of rotation 15 cm from one end. She wants you to tell her the period of this pendulum.

Physics
1 answer:
Anastasy [175]3 years ago
4 0

Answer:

The period of the pendulum is  T  =  1.68 \  sec

Explanation:

The diagram illustrating this setup is shown on the first uploaded image

From the question we are told that

     The length of the rod is L =  80 \ cm

       The diameter of the ring is d = 10 \ cm

       The distance of the hole from the one end  D =  15cm

From the diagram we see that point A is the center of the brass ring

 So the length from the axis of  rotation is mathematically evaluated as

          AP = 80 + 10 -5 -15  

          AP =  70 \ cm =  \frac{70}{100}  =  0.7 \ m

Now the period of the pendulum is mathematically represented as

             T  = 2 \pi  \sqrt{\frac{AP}{g} }

             T  =  2 \pi \sqrt{\frac{0.7}{9.8 } }

             T  =  1.68 \  sec

     

     

     

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Answer:

Explanation:

I got everything but i. Don't know why but it's eluding me. So let's do everything but that.

a. PE = mgh so

   PE = (2.5)(98)(14) and

   PE = 340 J

b. KE=\frac{1}{2}mv^2 so

   KE=\frac{1}{2}(2.5)(14)^2 and

   KE = 250 J

c. TE = KE + PE so

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   TE = 590 J

d. PE at 8.7 m:

   PE = (2.5)(9.8)(8.7) and

   PE = 210 J

e. The KE at the same height:

   TE = KE + PE and

   590 = KE + 210 so

   KE = 380 J

f. The velocity at that height:

   380=\frac{1}{2}(2.5)v^2 and

   v=\sqrt{\frac{2(380)}{2.5} } so

   v = 17 m/s

g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:

   590 = KE + PE and

   PE = (2.5)(9.8)(11.6) so

   PE = 280 then

   590 = KE + 280 so

   KE = 310 then

   310=\frac{1}{2}(2.5)v^2 and

   v=\sqrt{\frac{2(310)}{2.5} } so

   v = 16 m/s

h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:

   v=v_0+at and

   26 = 0 + 9.8t and

   26 = 9.8t so the time at 26 m/s is

   t = 2.7 seconds. Now we use that in the equation for displacement:

   Δx = v_0t+\frac{1}{2}at^2 and filling in the time the object was at 26 m/s:

   Δx = 0t + \frac{1}{2}(-9.8)2.7)^2 so

   Δx = 36 m

i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.

4 0
2 years ago
An object must move in the (same or different) direction as the force is being applied.
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Answer:

only reason an object will move in a different direction to the net force on it is because of its prior momentum and it will always accelerate in the direction of the force if thats what u mean.. lol

Explanation:

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2 years ago
A 51-kg woman runs up a vertical flight of stairs in 5.0 s. Her net upward displacement is 5.0 m. Approximately, what average po
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Answer:

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We note that power, P = The rate at which work is done = Work/Time

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Given that the vertical displacement = 5.0 m, we have

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g = Constant = 9.81 m/s²

h = 5.0 m

Also, time, t = 5.0 s

Total work done = 51 kg × 9.81 m/s²× 5 m = 2501.55 kg·m²/s² = 2501.55 J

P = 2501.55 J/(5 s) = 500.31 J/s = 500.31 W ≈ 500 W = 0.5 kW.

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Explanation:

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<u />

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Elastic deformation bends an object, whereas repulsion returns it to its original shape. This instrument is nothing more than an oscillating rod or pendulum that begins to vibrate when a tremor occurs. The vibration system has a pin. The pen records seismic waves on a sheet of paper that moves underneath. By studying these waves scientists can create a complete map of earthquakes.

Learn more about Seismograph construction here:-brainly.com/question/16047884

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