Given:
There are given the edge of the cube-shaped aquarium has 3 feet.
Explanation:
To find the value, we need to use the volume of the cube formula:
So,
From the formula of volume:
Where
a represents the value of edge.
So,
Put the value of edge into the above formula:
Then,
Now,
The water has a density of 62 pounds per cube foot.
According to the question:
If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:
Final answer:
Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.
And,
No, the density of water would not change.
9*14=126 126/3=42. the answer is 42 bags. hope this helps. Mark me as Brainliest
Answer:
<h3>18</h3>
Step-by-step explanation:
From the given diagram;
FGH = 49
GH = 31
Using the expression to get FG;
FG + GH = FGH
FG + 31 = 49
FG = 49-31
FG = 18
Hence the measure of FG is 18
Answer:
180 = (7x +5)+(3x -5 ) + 90
180 = 10x +90
10x = 90
x= 9
35 is the 20% so you multiply 35x5=175. 175 is the whole thing so you minus 175-35=140 which is the remaining money so half of that is 70