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2 years ago

11

Any help would be great

1 answer:

navik [9.2K]2 years ago

3 0

I believe the perimeter is 45 feet

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How do you graph x = 40?

Pani-rosa [81]

Answer:

Step-by-step explanation:

Draw an infinite vertical line on the +40 x axis.

5 0

2 years ago

Read 2 more answers

Can you pls help me i reallly need it

yan [13]

Answer:

D

Step-by-step explanation:

$49 one time payment so it is added.

$25 per month and he pays for a year(12 months) = 12 times 25

$49 + (12 × 25)

4 0

2 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

If one of the zeros of the cubic polynomial x3 + ax2 + bx + c is -1, then what will be the product of the other two zeros?

zhenek [66]

Answer:

The product of the other two zeros is c

Step-by-step explanation:

Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:

sum of the roots = α + β + γ = -a

-1 + β + γ = -a

β + γ = -a + 1

αβ + αγ + βγ = b

-1(β) + (-1)γ + βγ = b

-β -γ + βγ = b

Also, the product of the zeros is equal to -c, hence:

αβγ = -c

-1(βγ) = -c

βγ = c

Hence the product of the other two zeros is c

6 0

3 years ago

Tessa is training for a marathon she runs 13 km a day for 3 days

creativ13 [48]

nice

i think there's supposed to be more to the problem lol

4 0

2 years ago

Read 3 more answers