sp2 Hybridization. The valence orbitals of a central atom surrounded by three regions of electron density consist of a set of three sp2 hybrid orbitals and one unhybridized p orbital.
<h3>How do you describe hybrid orbitals?</h3>
A hybrid orbital is an orbital formed by the combination of two or more atomic orbitals. The resulting orbital has a different shape and energy than the component orbitals that form it. Hybridization is used to model molecular geometry and to explain atomic bonding.
<h3>What is the hybridization of the s atom?</h3>
The middle S atom containing the 5 valence atomic orbitals is basically hybridized to form five sp3d hybrid orbitals. In 2P-orbitals, four hybrid orbitals are overlapped and the fifth one contains a lone pair.
Learn more about hybrid orbitals here:
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Answer:</h3>
The structure of Electrophile (2-methylpropan-2-ylium) is shown in attached picture highlighted by green color.
<h3>Explanation:</h3>
Electrophiles are those species which are electron deficient and loves electron. These species often carry positive charge or contain atoms which have incomplete octet.
Also, we know that Benzene undergo Electrophilic Substitution reactions in which hydrogen atom is replaced by other electrophile. In given statement the electrophile to be reacted with benzene to form tert-Butylbenzene is generated from 2-methylpropene. 2-methylpropene when treated with phosphoric acid adds one proton across the double bond (electrophilic addition reaction) and generate a positively charged tertiary carbocation (stable) (highlighted green) which acts as an electrophile. Further on reaction with benzene this electrophile is substituted with proton and results in the formation of tert-Butylbenzene.
Answer:
8.45 moles are produced
Explanation:
CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl
From the equation, we can see that for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl
to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts
these is because for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl
therefore we have every 1x8.45(8.45) mole of CaCl₂ and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl
8.45 moles are produced in the reaction
This is the balanced equation H2+Cl3 -> 2HCl.
Answer:
80 mL
Explanation:
Step 1: Given data
- Initial pressure of hydrogen (P₁): 360 mmHg
- Initial volume of hydrogen (V₁): 240 mL
- Final pressure of hydrogen (P₂): 1080 mmHg
- Final volume of hydrogen (V₂): ?
Step 2: Calculate the final volume of hydrogen
If we assume ideal behavior and constant temperature, we can calculate the final volume occupied by hydrogen using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 360 mmHg × 240 mL/1080 mmHg = 80 mL