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kodGreya [7K]
3 years ago
14

Which of these is not a layer of skin?

Chemistry
2 answers:
givi [52]3 years ago
8 0

Answer would be:
D. Hyper-dimes
nalin [4]3 years ago
6 0
D. the hyper-dimes

hop the helps
good luck
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What are some sources of error associated with electroplating​
BARSIC [14]

Answer:

Cold Shuts. Cold shuts are one of the most common defects found in materials sent for electroplating.

Pitting

Sharp Edges

Cleavage Points

Unclean Manufacturing

Loss of Adhesion

Cracking After Plating — Hydrogen Cracking

Dull and Hazy Deposits in Plating.

Explanation:

5 0
3 years ago
Which of the following compounds contains the tin (IV) ion? A. SnO2 B. SnCl2 C. Sn2O D. Sn4O3
Zolol [24]
<span>A. SnO2 is the correct answer. I hope this helps </span>
3 0
3 years ago
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Which is a function of the gallbladder
Alinara [238K]

Answer:

<h3>Gall Bladder:</h3>

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7 0
3 years ago
A 0.500-g sample containing Na2CO3 plus inert matter is analyzed by adding 50.0 mL of 0.100 M HCl, a slight excess, boiling to r
Yakvenalex [24]

The percentage by mass of Na2CO3 in the sample is 48%.

The equation of the reaction of Na2CO3 with HCl;

Na2CO3(aq) + 2HCl(aq) ------> 2NaCl(aq) + H2O(l) + CO2(g)

Since the HCl is in excess, the excess is back titrated with NaOH as follows;

NaOH (aq) + HCl(aq) ---->NaCl(aq) + H2O(l)

Number of moles of HCl added =  0.100 M × 50/1000 L = 0.005 moles

Number of moles of NaOH added = 5.6/1000 ×  0.100 M = 0.00056 moles

Since the reaction of NaOH and NaOH is 1:1, 0.00056 moles of HCl reacted with excess HCl.

Amount of HCl that reacted with Na2CO3 =  0.005 moles -  0.00056 moles = 0.0044 moles

Now;

1 mole of Na2CO3 reacts with 2 moles of HCl

x moles of Na2CO3 reacts with 0.0044 moles of HCl

x = 1 mole × 0.0044 moles / 2 moles

x = 0.0022 moles

Mass of Na2CO3 reacted = 0.0022 moles × 106 g/mol = 0.24 g

Percentage of Na2CO3  in the sample = 0.24 g/ 0.500-g × 100/1 = 48%

Learn more about back titration: brainly.com/question/25485091

5 0
2 years ago
Radon-222 is a radioactive gas with a half-life of 3.82 days. How long would it take for fifteen-sixteenths of a sample of radon
Fittoniya [83]
Use the formula in terms of half life from the normal exponential functions 
<span>
N(t) = N(0) (1/2) ^ (t/thalf) </span>
<span>
N(0) is the original quantity </span>
<span>
N(t) = quantity remaining at time t </span>
<span>
t is the time </span>
<span>

thalf is half life </span>
<span>
1/16 = (1/2)^(t/3.82) </span>
<span>
16 = 2^(t/3.82) </span>
<span>
4 = t/3.82 </span>
<span>
t = 15.28 days

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
8 0
3 years ago
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