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2 years ago

Which describes the molecule below?

Chemistry

1 answer:

Ira Lisetskai [31]2 years ago

4 0

C. A lipid with three unsaturated fatty acids.
(got the question correct on a test)

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Identify the highlighted secondary lymphatic tissue located on the lateral wall of the oropharynx just inferior to the soft pala

Katena32 [7]

Answer:

The correct answer is - palatine tonsils .

Explanation:

Palatine tonsils or more normally tonsils are the pair of soft tissue masses of highlighted secondary lymphatic tissue present on the lateral wall of the oropharynx in the tonsilar fossa just below to the soft plate. It is the lymphatic tissue that is located to inferior to the soft plate.

Thus, the correct answer is - palatine tonsils.

6 0

2 years ago

Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a s

disa [49]

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R $HSO_4^-$ ⇄ $H^+ + SO_4^2^-$

I $0.14$

C $- x$ $+x$ $+x$

E $0.14-x$ $x$ $x$

$K_a = 1.3$ × $10^-^2$ for $HSO^-_4$ . As a result,

$\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a$

$K_a$ is large. It is no longer valid to approximate that $[HSO^-_4]$ at equilibrium is the same as its initial value.

$\frac{x^2}{0.14-y} = 1.3 * 10^-^2$

$x^2+1.3*10^-^2x - 0.14$ × $1.3$ × $10^-^2= 0$

Solving the quadratic equation for $x , x \geq 0$ since $x$ represents a concentration;

$x=0.0366538$

Then, round the results to 2 significant figure;

$[SO_4^2^-] = x = 0.037 mol. L ^-^1$
$[H^+] = x = 0.037 mol. L ^-^1$
$[HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1$

Learn more about concentration here:

brainly.com/question/14469428

#SPJ4

3 0

1 year ago

Identify the number and type of atoms in the following molecules.

Otrada [13]

Nitrogen atomic# 7 7protons, 7electrons, 7 neutrons

Oxygen atomic# 8 8protons, 8electrons, 8neutrons

Phosphorous atomic# 15 15protons, 15 electrons, 15 neutrons

Sulfur atomic#16 16protons, 16electrons, 16 neutrons

5 0

3 years ago

A 2.00 kg piece of lead at 40.0°C is placed in a very large quantity of water at 10.0°C,and thermal equilibrium is eventually re

sveticcg [70]

Answer:

Δ S = 26.2 J/K

Explanation:

The change in entropy can be calculated from the formula -

Δ S = m Cp ln ( T₂ / T₁ )

Where ,

Δ S = change in entropy

m = mass = 2.00 kg

Cp =specific heat of lead is 130 J / (kg ∙ K) .

T₂ = final temperature 10.0°C + 273 = 283 K

T₁ = initial temperature , 40.0°C + 273 = 313 K

Applying the above formula ,

The change in entropy is calculated as ,

ΔS = m Cp ln ( T₂ / T₁ ) = (2.00 )( 130 ) ln( 283 K / 313 K )

ΔS = 26.2 J/K

6 0

3 years ago

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Greeley [361]

B, the height above or below sea level

3 0

3 years ago