By Question it's given that the sum of two numbers is 15 . And we need to find out the numbers. So ,
<u><em>Let </em><em>us </em><em>take</em><em> </em><em>:</em><em>-</em><em> </em></u>
- First number = x
- Second number = x + 1
<em><u>According</u></em><em><u> to</u></em><em><u> the</u></em><em><u> Question</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
<em><u>Therefore</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
- First number = 7
- Second number = 8
<u>Hence</u><u> the</u><u> </u><u>two </u><u>numbers</u><u> </u><u>are </u><u>7</u><u> </u><u>and </u><u>8</u><u>. </u>
Answer:3/8.
Step-by-step explanation:
Find the GCD (or HCF) of numerator and denominator
GCD of 24 and 64 is 8
Divide both the numerator and denominator by the GCD
24 ÷ 8
64 ÷ 8
Reduced fraction:
3
8
Therefore, 24/64 simplified to lowest terms is 3/8.
Answer:
d=8
Step-by-step explanation:
Answer:
24 square units
72 square units
96 square units
Step-by-step explanation:
In the figure attached, the complete question is shown.
One face is a rectangle with length = 12 and width = 8. Its area is: 8*12 = 96 square units
Another face is a rectangle with length = 12 and width = 10. Its area is: 10*12 = 120 square units
Another face is a rectangle with length = 12 and width = 6. Its area is: 6*12 = 72 square units
The other two faces are right triangles with base = 6 and height = 8. Their area is: (6*8)/2 = 24 square units