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Gennadij [26K]
3 years ago
7

What’s the answer to this question

Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0
     6 x^{3} + 3x + 5
-    2x^{2} + 6x + 5
-----------------------------------------
      4x - 3 + 0
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Which inequalities are true? Check all that apply. Three-fifths < 0 Four-sixths greater-than one-half Nine-elevenths < 1 T
Kipish [7]

\frac{3}{5} < 0

\frac{8}{16} > \frac{1}{2}\\\\

<em><u>Solution:</u></em>

<em><u>We have to find the inequalities that are true</u></em>

<em><u>Option 1</u></em>

\frac{3}{5} < 0\\\\0.6 < 0

0.6 is not less than 0

Thus this inequality is not true

<em><u>Option 2</u></em>

\frac{4}{6} > \frac{1}{2}\\\\0.667 > 0.5

0.667 is greater than 0.5

Thus this inequality is true

<em><u>Option 3</u></em>

\frac{9}{11} < 1\\\\0.818 < 1

0.818 is less than 1

Thus this inequality is true

<em><u>Option 4</u></em>

\frac{8}{16} > \frac{1}{2}\\\\

0.5 = 0.5

Thus the above inequality is not true

6 0
3 years ago
Could you please help me to solve this query??
galina1969 [7]

Answer:

Show me problem

Step-by-step explanation:

I need a problem to solve it

3 0
3 years ago
Move the decimal point 4 places right to find , a number greater than or equal to 1 and less than 10. Then multiply by 10 , usin
JulsSmile [24]
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8 0
3 years ago
Solve the equation. | x | -7 =6
guapka [62]
Hi there!

Let's solve this equation step by step!
|x|  - 7 = 6

First add 7 to both sides.
|x|  = 13



Next we need to take a look at the meaning of the stripes between our variable. Those stripes mean we are dealing with an absolute value function. The absolute value stripes make everything between the stripes positive; also when we plug in a number. In this particular question we can plug in both -13 and 13 at the position of n, because when -13 is made positive, it fulfils the equation.

Hence,
x= 13 or x = - 13

~ Hope this helps you!
6 0
4 years ago
Read 2 more answers
The ratio of the circumferences of two circles 2 : 5. Find the ratio of their areas
ratelena [41]
Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
Area1:Area2=pi(2R)^2:pi(5R)^2=pi(4R^2):pi(25R^2), pi cancel out we get
4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
5 0
3 years ago
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