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Answer:
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
1. To find the x-intercept, replace y in the equation with 0, then solve for x.
... To find the y-intercept, replace x in the equation with 0, then solve for y.
If the equation is easily put into the form
... x/a + y/b = 1
Then the x-intercept is "a" and the y-intercept is "b".
2. Let's graph 3x+4y = -12.
If we divide the equation by -12, we can put it into the form
.. x/(-4) + y/(-3) = 1
This equation has x-intercept -4 and y-intercept -3.
(If you know the intercepts, you can simply draw the line through them to graph your linear equation.)
