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Alex_Xolod [135]
4 years ago
7

Krista's softball team played 35 games this season and lost only 7 of them.

Mathematics
2 answers:
DaniilM [7]4 years ago
7 0
I hope this helps you

ZanzabumX [31]4 years ago
7 0

The fraction \frac{7}{35} represents how many games Krista's softball team lost out of the 35 games Krista's team played.

To find the percent of games that Krista's team lost, we need to turn the fraction \frac{7}{35} into a percent.

We can reduce \frac{7}{35} by dividing both the numerator and denominator by the Greatest Common Factor of 7 and 35 using 7.

7 ÷ 7 = 1

35 ÷ 7 = 5

Now, we have our reduced fraction.

1 ÷ 5 = 0.2

0.2 × 100 = 20%

Therefore, Krista's softball team lost 20% of their games.

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4 0
2 years ago
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In a NiCd battery, a fully charged cell is composed of Nickelic Hydroxide. Nickel is an element that has multiple oxidation stat
Westkost [7]

Answer:

P(cell has at least one of the positive nickel-charged options) = 0.83.

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.

Step-by-step explanation:

It is given that the Nickel Charge Proportions found  in the battery are:

0 ==> 0.17

.

+2 ==> 0.35

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+3 ==> 0.33

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The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.

a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 -  P(a cell has +4 nickel-charged options)  '.' because +4 is only positive nickel charge greater than +3      

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To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!

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