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3 years ago

What is the solution to the following question

Mathematics

1 answer:

Anastaziya [24]3 years ago

4 0

Answer:

Step-by-step explanation:

2(x + 1) = 3(5 - x) + 2

Distribute,

2(x + 1) = 3(5 - x) + 2

2x + 2 = 3(5 - x) + 2

Rearrange terms,

2x + 2 = 3(5 - x) + 2

2x + 2 = 3(-x + 5) + 2

Distribute,

2x + 2 = 3(-x + 5) + 2

2x + 2 = -3x + 15 + 2

Add the numbers,

2x + 2 = -3x + 15 + 2

2x + 2 = -3x + 17

Subtract 2 from both sides,

2x + 2 = -3x + 17

2x + 2 - 2 = -3x + 17 - 2

2x = -3x + 17 - 2

2x = -3x + 15

Add 3x to both sides,

2x = -3x + 15

2x + 3x = -3x + 3x + 15

5x = -3x + 3x + 15

5x = 15

Divide both sides by the same factor (15),

5x = 15

5x/5 = 15/5

x = 15/5

x = 3

Hence, the answer is 3.

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6 veces un numero elevado al cuadrado.

Lunna [17]

Answer:

Six squared=36

Step-by-step explanation:

Well, we know squared means 2

So...Think.

Six is not times 2. You might think that, but...

...It's actually multiplying 6 two times

6x6 is 36

You also can think of it as

6x(6 two times)

or 6x(3x2)

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4 0

3 years ago

What is the volume of the following rectangular prism?<br><br><br><br><br> Volume =_____units^3

Ber [7]

The formula of a volume of a rectangular prism:

$V=BH$

B - area of a base

H - height

The green rectangle is the base.

We have:

$B=3\dfrac{1}{3}=\dfrac{3\cdot3+1}{3}=\dfrac{10}{3}$

and

$H=1\dfrac{2}{5}=\dfrac{1\cdot5+2}{5}=\dfrac{7}{5}$

Substitute:

$V=\dfrac{10\!\!\!\!\!\diagup^2}{3}\cdot\dfrac{7}{5\!\!\!\!\diagup_1}=\dfrac{14}{3}=4\dfrac{2}{3}$

<h3>Answer: The volume of the following rectangular prism</h3><h3> is 4 2/3 u³.</h3>

3 0

4 years ago

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A line connecting (5, 6) to another point has an undefined slope. What is the closest point on this line with whole number coord

vivado [14]

Let's start off like this:
This is a line connecting to another that has an undefined slope, so X had to be 5 for all the values of Y. The coordinates could be (5,6) or (5,4).

7 0

4 years ago

The question is attached

DerKrebs [107]

$cos(A - B) = cos A cos B + sin A sin B$

In this case, A is $\frac{\pi }{3}$ and B is $\frac{\pi }{5}$ , so:

$cos\frac{\pi}{3} cos\frac{\pi}{5} +sin\frac{\pi }{3} sin\frac{\pi }{5} =cos(\frac{\pi}{3} -\frac{\pi}{5} ) = cos\frac{2\pi}{15}$

Hope that helps!

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2 years ago

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Answer:

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3 years ago