Would be x^2-5-6 so the 0s would be (x-6)(x+1) so 6 and -1
Answer:
Hola que hace
:I
Step-by-step explanation:
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Slope formula:
y2 - y1
_____
x2 - x1
5 + 16
_____
18 + 8
21
__
26
slope is 21/26
Answer:
TRUE
Step-by-step explanation:
2x + 0.8/y = z – 4
x = 7, y = 0.2, z = 22
2×7 + 0.8/0.2 = 22 - 4
14 + 4 = 18
18 = 18
TRUE.
