Atomic number (Z) of tungsten is 74
Mass number (A) of tungsten is 184
Now:
Atomic number of an element = Number of protons = Number of electrons
Mass number = Number of Protons + Number of neutrons
In the case of tungsten
Total Number of electrons = 74
Jeffrey has already added 21 electrons
Number of electrons needed = 74 - 21 = 53
Ans (D) 53 more electrons are needed to complete the neutral atom of tungsten.
<em>A: Endoplasmic Reticulum, Chloroplasts </em>
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Answer:
Therefore the equilibrium number of vacancies per unit cubic meter =2.34×10²⁴ vacancies/ mole
Explanation:
The equilibrium number of of vacancies is denoted by
.
It is depends on
- total no. of atomic number(N)
- energy required for vacancy
- Boltzmann's constant (k)= 8.62×10⁻⁵ev K⁻¹
- temperature (T).

To find equilibrium number of of vacancies we have find N.

Here ρ= 8.45 g/cm³ =8.45 ×10⁶m³
= Avogadro Number = 6.023×10²³
= 63.5 g/mole

g/mole
Here
=0.9 ev/atom , T= 1000k
Therefore the equilibrium number of vacancies per unit cubic meter,

=2.34×10²⁴ vacancies/ mole
Answer:
active transport
Explanation:
passive transport does not involve energy