Answer:
C. 1.3 mol
Explanation:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is universal gas constant,
and T is absolute temperature.
Given:
P = 121.59 kPa
V = 31 L
T = 360 K
R = 8.3145 L kPa / mol / K
Find: n
n = PV / (RT)
n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)
n = (3769.29 L kPa) / (2993.22 L kPa / mol)
n = 1.26 mol
Round to two significant figures, there are 1.3 moles of gas.
Answer:
Explanation:
The amine functional group is obtained by subsititution of one or more hydrogen atoms in the ammonia compound.
Ammonia is NH₃.
Then,
- by substituting one hydrogen you obtain R - NH₂.
- by substituting two hydrogens you obtain R' - NH - R''
- by subsituting the three hydrogens you obtain:
R'''
|
R' - N - R''
In this case, the three subsitutuents are silyl groups. The silyl group is derived form silane and is SiH₃. So, the tcompound <em>trisilylamine</em> is:
SiH₃
|
SiH₃ - N - SiH₃
Thus, you can count 3 hydrogen atoms for every silylgroup for a total of <u><em>9 hydrogen atoms in each molecule of trisilylamine.</em></u>
Answer:
The answer to your question is 150 ml
Explanation:
Data
Volume 1 = 25 ml
Concentration 1 = 0.6 M
Volume 2 = ?
Concentration 2 = 0.1 M
Formula
Volume 1 x Concentration 1 = Volume 2 x Concentration 2
Solve for Volume 2
Volume 2 = (Volume 1 x Concentration 1)/Concentration 2
Substitution
Volume 2 = (25 x 0.6) / 0.1
Simplification
Volume 2 = 15 / 0.1
Result
Volume 2 = 150 ml
