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KonstantinChe [14]
3 years ago
9

A chemical reaction in which two elements or radicals change places with two other elements or radicals is a _ reaction

Chemistry
1 answer:
ASHA 777 [7]3 years ago
7 0
A chemical reaction in which 2 elements or atoms change places with two other elements and or reactive atoms would be a double displacement or double replacement reaction.
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What are the oxidation numbers for groups 1-18 (skip groups 3-12)
Brilliant_brown [7]
Group 1: +1
Group 2: +2
Group 13: +3
Group 14: +4
Group 15: -3
Group 16: +II
Group 17: -1
4 0
2 years ago
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All scientists try to base their conclusions on?
Rama09 [41]
All scientists try to base their conclusions on data and measurements.
5 0
3 years ago
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What is wrong with this chemical<br> equation - N2 + O2 → 2N20,
LUCKY_DIMON [66]

Answer and Explanation:

I think the thing that is wrong with this chemical equation is that there is 0 by the 2 instead of the letter O.

Other than that, everything would be balanced.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

5 0
2 years ago
Read 2 more answers
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
How many grams are 3.01 × 1023 molecules of CuSO4?
zvonat [6]
Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.
4 0
3 years ago
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