4.6to the twelth power plus ten or something like that it has been a while since I have done the scientific notation but where ever you put in the number of zeros. is twelve
Answer:
A. They are nonreactive gases
Answer:
I hope this helps 52.2 g/mol
Explanation:
1) Solve for the moles using PV = nRT:
n = PV / RT
n = [(700.0 mmHg / 760.0 mmHg atm¯1) (48.0 L)] / [(0.08206 L atm mol¯1 K¯1) (293.0 K)]
n = 1.8388 mol
2) Divide the grams given (96.0) by the moles just calculated above:
96.0 g / 1.8388 mol = 52.2 g/mol
Answer:
<h3>The answer is 526.32 mL</h3>
Explanation:
To find the original volume we use the formula for Boyle's law which is
Since we are finding the original volume
From the question we have
We have the final answer as
<h3>526.32 mL</h3>
Hope this helps you
Answer:
280 mL
Explanation:
Given data:
Mass of CuSO₄ = 55.75 g
Molarity of CuSO₄ = 1.25 M
Volume of CuSO₄ = ?
Solution:
First of all we will calculate the number of moles.
Number of moles:
Number of moles = mass / molar mass
Number of moles = 55.75 g/ 159.6 g/mol
Number of moles = 0.35 mol
Volume of CuSO₄:
Molarity = number of moles / volume in litter
1.25 M = 0.35 mol / volume in litter
Volume in litter = 0.35 mol / 1.25 M
Volume in litter = 0.28 L
Volume in milliliter:
0.28 L × 1000 mL/ 1 L = 280 mL
