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KonstantinChe [14]
4 years ago
9

A chemical reaction in which two elements or radicals change places with two other elements or radicals is a _ reaction

Chemistry
1 answer:
ASHA 777 [7]4 years ago
7 0
A chemical reaction in which 2 elements or atoms change places with two other elements and or reactive atoms would be a double displacement or double replacement reaction.
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What is ionic bond,,,?​
andreev551 [17]

Answer:

An ionic bond is the bonding between a non-metal and a metal, that occurs when charged atoms (ions) attract.

Explanation:

Here I put the function of Iconic Bond.

  • <em>Ionic bonds form so that the outermost energy level of atoms are filled. Ion. an atom or group of atoms that bring out a positive or negative electric charge as a result of having lost or gained one or more electrons.</em>

<em>Therefore, I hope this helps!</em>

7 0
2 years ago
Read 2 more answers
True or false?<br><br> When sodium and chlorine combine and bond, a molecule is formed.
CaHeK987 [17]

When Sodium and Chlorine come together they transfer an electron.

- Source: google


Hopefully this was clear and you understood!

3 0
3 years ago
An aqueous solution contains 32.7% KCl (wt/wt%). what is the mole fraction of KCl in the solution
inna [77]

The mole fraction of KCl in the solution is 0.1051

calculation

mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)

moles=mass/molar mass

mass of KCl=32.7g

molar mass of KCl= 39 +35.5

moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles

find the moles of H2O= mass of H2O/molar mass

mass of H2O=100-32.7=67.3g

molar mass of H2O=( 1 x2) +16=18 g/mol

moles = 67.3/18 =3.739 moles

total moles=3.739+0.439=4.178 moles

mole fraction is therefore=0.439/4.178=0.1051

5 0
3 years ago
What element has 4 valence electrons and 5 electron shells?
marta [7]

Answer:  Tin (Sn)

Explanation:  The electron configuration for tin (Sn) is shown in the picture.  It's last electrons are:

5s^2 4d^10 5p^2

The valence electrons are in the 5th electron shell and include 2 each in the 5s and 5p orbitals.

8 0
3 years ago
What is the answers and pls show work if possible!!
taurus [48]

D = m / V


It even gives you the density of gold in the problem. Major hint. Once you know the volume (using V = m / D) then you can calculate the height (thickness) from the equation...


V = L x W x H

Volume = Length x Width x Height


start by converting 200.0 mg into grams

1000 mg = 1 g

200. mg x (1 g / 10^3 mg) = 0.200 g


V = m / D

V = 0.200 g / (19.32 g/cm^3)

V = 0.01035 cm^3


Convert 2.4 ft and 1 ft to cm

2.4 ft x (12 in / 1 ft) x (2.54 cm / 1 in) = 73.15 cm

1 ft = 30.48 cm


Compute the height (thickness)

V = LxWxH

H = V / LW = 0.01035 cm^3 / 73.15 cm / 30.48 cm

H = 4.64 x 10^-6 cm


Convert to nanometers

4.64 x 10^-6 cm x (1 m / 100 cm) x (10^9 nm / 1 m) = 46.4 nm


Knowing the atomic radius of gold, I might have asked my students for the minimum number of gold atoms in this thickness of gold. This would assume that the gold atoms are all in a row. This would give the minimum number of gold atoms.


Atomic radius gold = 174 pm

Diameter = 348 pm


46.4 nm x (1 m / 10^9 nm) x (10^12 pm / 1 m) x (1 Au atom / 248 pm) = 133 atoms of gold


4 0
3 years ago
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